2^10=10^3We assume an average height of 1750, 1500 of which are fillable feet, dimensions 15*1*1, and that Orangutans achieve maximum compression at the volume of a 3 ft by 2 ft by 2 ft cube.
That gives us total volume of 5*1.2E2^2*1500 ft = 6E4*1.5E3 = 9E7 ft^3, and 12 ft ^3 for orangutans gives 9E7/12 = 7.5E6 orangutans.
The extra credit question is bogus, he didn't specify African or European swallow.
How many digits are in the largest known prime, 2^43,112,609 - 1 ?
<quizbowl> ey kid ya want some shortbread
<EASTstroudsburg13> I don't know why, but I just can't bring myself to delete this post.
I assume my gamma you mean the E-M one,(e^(pi^(gamma^(phi))))
I will guess that a hard drive would be a better indicator of data density than a flash drive. I believe the best hard drives have a current capacity of around 10^13 bytes (10 terrabytes) and are probably 5x5x2 or 50cm^3 Thus you can store 0.5E12 or 5*10^11 bytes in one centimeter. Actually, I will round that up to a terrabyte per cubic centimeter, as even hard drives have considerable infrastructure. That would be 10^18/cubic meter or 10^24 bytes per cubic kilometer. The earth has a radius of 6000km, and I know the moon is a fraction, so I will guess about 2000km, thus it has a volume of 4*8*10^9 km^3 or 2*10^10 cubic kilometers. Therefore I will assume the moon can hold 10^34 bytes of data I am not completely sure about how much data per second 1080 is, but I will guess 10mb/s or 10^7/s, so thus the moon can hold 10^27 seconds of video.If we build a data storage device that was the size of the moon, with our present maximum storage capacity density, how many seconds of 1080p video could it hold?
Assumptions: Car gets 20mpg, Dallas to Chicago is 2E3 miles, Ink cartrige is 20 ml and costs 25$, 2L is 1 gallonIf cars were to run on the ink out of printer cartridges with the same "ink efficiency" as gas efficiency, how much would you spend on ink to drive from Dallas, TX to Chicago, IL?
Okay, this is going to be a stream-of-consciousness problem.Assumptions: Car gets 20mpg, Dallas to Chicago is 2E3 miles, Ink cartrige is 20 ml and costs 25$, 2L is 1 gallonIf cars were to run on the ink out of printer cartridges with the same "ink efficiency" as gas efficiency, how much would you spend on ink to drive from Dallas, TX to Chicago, IL?
Then it is simple multiplication and division, giving 2E3/20*2*1000/20*25 = 2.5E5
What is the 1,000,000th prime number? (This was on my regional test) If stuck, use prime number theorem.
<quizbowl> ey kid ya want some shortbread
<EASTstroudsburg13> I don't know why, but I just can't bring myself to delete this post.
Ok, so silver nitrate itself is a bit expensive. I flipped through Ward's a few weeks ago and I remember that like 25 grams was about E2 dollars or so. I think. So multiply by 4E1 and you get E3 dollars (whoa, expensive!)What is the cost of a kilogram of Silver nitrate?
<quizbowl> ey kid ya want some shortbread
<EASTstroudsburg13> I don't know why, but I just can't bring myself to delete this post.
Just for the record, a gallon is actually about 4L, so your answer should be 5E5, and therefore 6 rather than 5.Assumptions: Car gets 20mpg, Dallas to Chicago is 2E3 miles, Ink cartrige is 20 ml and costs 25$, 2L is 1 gallonIf cars were to run on the ink out of printer cartridges with the same "ink efficiency" as gas efficiency, how much would you spend on ink to drive from Dallas, TX to Chicago, IL?
Then it is simple multiplication and division, giving 2E3/20*2*1000/20*25 = 2.5E5
Molecular weight of silver is about 100, nitrate is 14 + 3(16) = 60ish (both slightly low), so silver nitrate is 5/8 silver by mass; let's say the cost of silver nitrate is determined entirely by the cost of the silver it contains, so you have 5/8 kilo of silver, or 6.25E-1 kg; silver is roughly $30/oz, one ounce is 28g or 2.8E-2 kg:What is the cost of a kilogram of Silver nitrate?
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