After someone answers this, can you please explain it? I guess you're going to have to try to figure out how many photons a roomful of typical lightbulb emits during the time it would take a photon to be absorbed... is that along the right lines? But I have no idea how to calculate it. Would you learn about that in physics?At a given instant, how many photons are in a room of your choice (with electric lighting turned on)?
*Also consider only the photons emitted by the electric lights, ignoring thermal radiation of other objects, virtual photons, etc.
I meant that if one were to freeze time and count every photon traveling from the lights to somewhere in the room, how many photons would one count.After someone answers this, can you please explain it? I guess you're going to have to try to figure out how many photons a roomful of typical lightbulb emits during the time it would take a photon to be absorbed... is that along the right lines? But I have no idea how to calculate it. Would you learn about that in physics?At a given instant, how many photons are in a room of your choice (with electric lighting turned on)?
*Also consider only the photons emitted by the electric lights, ignoring thermal radiation of other objects, virtual photons, etc.
I will make the assumption that this is referring to specifically Fermi questions, as opposed to solving problems with the same methodology, which would be extremely difficult to calculate. Based on the number of tournaments and the average length of tests (20 questions from my experience), I would guess there may be as many as E4 questions from Science Olympiad alone, plus when they are used separately for others purposes, I will answer with 4.Here's a semi-guess solution which may be close. Assume a room is 25 meters*10 meters=250 meters. Assume a photo is around 1/10^5 of a meter, so therefore we get FA=7. This may be very off, since a photon is not around 1/10^5 of a meter, but it's an OK estimate.
New question: Find the number of fermi questions made anywhere up to this point.
SeemsLegit, I agree with your assumptions that (1) shoe production in China is dominated by domestic rather than exports (2) the average Chinese person uses 1 pair of shoes per year (3) we should neglect the fact that space is lost when packing rice into a container.Let's say an average shoe is 3 inches*12 inches=36 inches (looking at my own foot, which may be a bit large, I'm size 11. So let's change it to 25 inches. Let's also say they make the number of shoes for EVERYBODY in China which is a LOT of people (1 billion). Therefore, we get 10^9 people, with 25 inches per shoe. And now, a grain of rice takes up 1 inch*1/10 inch=1/10 inch. Therefore, we get 10^9*25/(1/10) or FA=10 yay.
Calculate the number of fedoras in the world.
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