Simple Machines B/Compound Machines C Question Marathon
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Re: Simple Machines B/Compound Machines C Question Marathon
I meant the distance from the middle of the base to the tip
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Re: Simple Machines B/Compound Machines C Question Marathon
Then I think it's right for a wedge then. However, for the inclined plane I think it's wrong, and should be length of incline over height (http://hyperphysics.phy-astr.gsu.edu/hb ... ac.html#c1)fantasyfan wrote:IMA of:
Pulley: number of strings supporting the mass
Lever: effort distance/load distance
Wedge: length/base width
Wheel and Axle: radius of wheel/radius of axle
Inclined Plane: Length of base/Height
Screw: Circumference/pitch
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Before you criticize a man, walk a mile in his shoes. That way you'll be a mile away and he'll be shoeless.
You should only create problems, that only you know solutions to.
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Re: Simple Machines B/Compound Machines C Question Marathon
Sorry, yes you are correct
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Re: Simple Machines B/Compound Machines C Question Marathon
What are some ways to increase the stability and balance of a first class lever?
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Re: Simple Machines B/Compound Machines C Question Marathon
More importantly, what can be changed to increase accuracy for calculations (much like the device portion of the competition)?
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Re: Simple Machines B/Compound Machines C Question Marathon
And for similar reasons, explain why using higher masses in calculations might increase your accuracy.
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Re: Simple Machines B/Compound Machines C Question Marathon
You lose sensitivity, as the ratio of the actual weights to the mass of your lever decreases. (When it's balanced, it's not as accurate this way). Think about it, when you have a heavier bar, it requires more force to move it then a lighter bar.
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Re: Simple Machines B/Compound Machines C Question Marathon
I don't believe your answer is right.lchs wrote:I'm not so sure about this but I'll give it a shot...Mathdino wrote:Suppose that the pulley in the below image is connected to something weighing 10 kg, and I need to pull on it with 9 N of force to hold it up. What's the efficiency? [img]http://02.edu-cdn.com/files/89501_89600/89569/file_89569.jpg[/img]
IMA = (Force out of the machine)/(Force into the machine). So for this scenario, the Force into the machine would be 9N, I think. And the Force out of the machine would be 10kg * 9.8m/s/s = 98N. Therefore, the IMA = 98N/9N = 10.89? I feel like I need to use the visual somehow, but this is what I ended up doing... :?
IMA is Ideal Mechanical Advantage.
IMA is calculated by distance. Not force.
It your were calculating a MA with force that would be AMA (Actual Mechanical Advantage).
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