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47, XY, +21
Since the genotype of the male isn't specified, he can have two possible genotypes. If the male has a genotype of AA, then the four children would be: Genotype- 2:2 (50% AA, 50% AB) Phenotype- 2:2 (50% type A, 50% type AB) If the male has a genotype of AO, then the four children would be: Genotype- 1:1:1:1 (25% AA, 25% AO, 25% AB, 25% BO) Phenotype: 2:1:1 (50% type A, 25% type AB, 25% type B)
There could be any of 4 different genotypes, and 3 different phenotypes. It's fairly evident that vennowsah is correct, so I believe he can ask a question anytime unless the person who asked the question comes on. But we don't need to debate small technicalities.
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