CHALLENGE: How many post-its would be required to fill the entire Pacific Ocean assuming it take the densest packing structure with no air gaps?

- A pad of like 200 post-its is 1 cm high. - Using the thing that it would take 10^16 post-its to completely cover the Pacific. - Assuming the Pacific is 5 km deep everywhere, and is a rectangular prism. - 5 km = 500,000 cm = 500,000 * 200 post-its = 100,000,000 post-its = 10^8 - 10^8 times 10^16 equals - Fermi Answer of 24

- On average the Pacific Ocean is 12,100 feet deep, or 3.688 km - Apparently one post-it is 0.03 inches thick, or 0.0762 cm. - This is 4.8 million post-its from the bottom of the ocean to the top, rounded to 10^6 - 10^6 times 10^16 equals - Fermi Answer of 22

How many American flags exist in the U.S. today?