Fermi Questions C

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Re: Fermi Questions C

Postby Raleway » May 31st, 2017, 10:52 am

Good try! The last answer would have received credit, and I'm pretty sure most wouldn't have gotten close e.e

How many years of sleep would the regular human need (avg based) to reach the total amount of time since the universe was created?
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Re: Fermi Questions C

Postby Adi1008 » May 31st, 2017, 1:34 pm

Good try! The last answer would have received credit, and I'm pretty sure most wouldn't have gotten close e.e

How many years of sleep would the regular human need (avg based) to reach the total amount of time since the universe was created?
My attempt
Assume one person sleeps 8 hours a day. There's 24 hours in a day, so it's 1/3 of the time. In three years, a person sleeps one year's worth of time. The universe is 13.7 billion years old, or 1.37 E10 years. Three times that is 4.11E10, giving a Fermi Answer of 10
Actual answer
[url=http://www.gallup.com/poll/166553/less-recommended-amount-sleep.aspx]This[/url] says that Americans get about 6.8 hours of sleep. That's one year of sleep every 3.53 years. Doing 3.53*1.37 E10 gives a Fermi Answer of 10 (although just barely)
How many US dollar bills would it take in order to create a stack from Mumbai to Istanbul?
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Re: Fermi Questions C

Postby Unome » May 31st, 2017, 1:46 pm

Stacked flat I assume?
- Guesstimating the distance is around 2.5E6 meters - Stacks of dollar bills - probably similar to paper, so 4E1 per centimeter = 4E3 per meter. - Multiply to get ~E10 Fermi Answer: 10
True Answer
- A single dollar bill is .0043 inches, which is ~9155 per meter - Using [url=http://www.gcmap.com/]this tool[/url], the distance is 2997 miles = ~4823204 meters - Multiply to get 4.4E10 - a good example of two bad estimates canceling out :P True Answer: 10
How many pieces of letter paper would it take to cover a single C60 carbon fullerene?
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Re: Fermi Questions C

Postby appleshake123 » May 31st, 2017, 11:07 pm

Guess
I know from some lab in chem a few years back that iron had an atomic radius of 125 pm. Carbon is higher to the right, so it is less, but by not to much, so carbon has an atomic radius of e-10 m. Surface area of a sphere b/c fullerene 4*pi*r^2, so surface area is 12(e-10)^2 = e-19m^2. Letter paper is 8.5"x11" or about 100in^2 *(6,25ish cm^2)* e-4 m^2 or about e-1 m^2. So to cover c60 carbon fullerene, you need e-18 letter paper. FA = -18
Internet answer
DIameter of fulleren is 7A or 7e-10, so Radius of 3.5e-10.. Surface area is 1.5 E-18. Letter paper is 6*e-2 m^2. You need about 2.5 E-17 of paper so FA = -17. I underestimated the surface area by not adjusting for the radius.
With fans blowing at a flat wooden board on the back of a skateboard, how many desktop fans is needed to propel the average man lying on the skateboard on a tennis court?
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Re: Fermi Questions C

Postby talkingturtle101 » June 12th, 2017, 5:24 pm

Bringing this thread back.
My Answer
- It would maybe take 500 J of energy to lift a person 1 foot off the ground. - A fan from a desktop could maybe provides 0.1 J, so Fermi Answer of 3
Actual Answer
- It takes 1.36 J to lift one pound one foot off the ground. So if a person weighs 150 pounds, this is about 200 J. - I couldn't find how much energy a desk fan could provide, but it might be 1 J, so Fermi Answer of 2? - Sorry for the really terrible answer.
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Re: Fermi Questions C

Postby Unome » June 13th, 2017, 11:42 am

Bringing this thread back.
My Answer
- It would maybe take 500 J of energy to lift a person 1 foot off the ground. - A fan from a desktop could maybe provides 0.1 J, so Fermi Answer of 3
Actual Answer
- It takes 1.36 J to lift one pound one foot off the ground. So if a person weighs 150 pounds, this is about 200 J. - I couldn't find how much energy a desk fan could provide, but it might be 1 J, so Fermi Answer of 2? - Sorry for the really terrible answer.
Btw we need a question to answer :)
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Re: Fermi Questions C

Postby Magikarpmaster629 » June 13th, 2017, 7:07 pm

Hey, would any of you be interested in a question marathon live for Fermi Questions? We did one for Fast Facts way back in like October (I'll find the link when I'm not on mobile) and I'd like to get a second one going (really should have done this earlier...)
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Re: Fermi Questions C

Postby NeilMehta » June 13th, 2017, 8:57 pm

Hey, would any of you be interested in a question marathon live for Fermi Questions? We did one for Fast Facts way back in like October (I'll find the link when I'm not on mobile) and I'd like to get a second one going (really should have done this earlier...)
I would love to join, but maybe later in the summer once all of us have wrapped up finals
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Re: Fermi Questions C

Postby talkingturtle101 » June 16th, 2017, 12:16 pm

Btw we need a question to answer :)
Whoops I forgot. During the time it takes Tchaikovsky's 1812 Overture to play, how many times could light go from the Earth to the moon?
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Re: Fermi Questions C

Postby Unome » June 16th, 2017, 1:44 pm

Nice one
- Estimated time it takes, 3 minutes, ~2E2 seconds (idk wild guess, maybe it's more because classical + why else would you mention it in a Fermi question?) - Light takes ~5E2 seconds to go to the sun and back, I'd estimate less than a hundredth as far to the moon (probably a lot closer actually, idk.), so ~5E-1 seconds - Therefore, E3 Fermi Answer: 3
True Answer
Tchaikovsky's 1812 Overture is 900 seconds long - The moon is 384,400 km away so it takes light around 1.2813 seconds for the round-trip - Dividing the two gives 702.41 seconds. Fermi Answer: 3
What was the average rate of text messages sent, in messages per second, during 2016?
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Re: Fermi Questions C

Postby John Richardsim » June 22nd, 2017, 6:31 pm

What was the average rate of text messages sent, in messages per second, during 2016?
My answer
Assuming 4 texts per person per day --> ~[strikethrough]30 billion[/strikethrough]3x10^10 texts per day --> divided by ~[strikethrough]100,000[/strikethrough]10^5 seconds per day --> ~3x10^5 texts per second -->10^5 --> FA=5
Actual answer
Using the Google machine yields the figure of 23 billion per day in 2015 (I wasn't able to find a figure for 2016 from the couple sites I clicked on, so I'll just use 2015). Divide this number by 86400 seconds per day to get 266,203 = 2.7x10^5. FA=5 Source: https://teckst.com/19-text-messaging-stats-that-will-blow-your-mind/
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Re: Fermi Questions C

Postby Unome » June 23rd, 2017, 6:38 am

My Answer
- I have no idea how big crater lake is, nor can I even remember what it is. I'll guess 500 km^2 and 200 meters deep, which gives a total volume of E2 cubic kilometers which equals E11 cubic meters. - This is equal to E17 milliliters. - A diet coke is probably like E2 milliliters, so E15 Fermi Answer: 15
Actual Answer
The volume of Crater Lake (which is apparently in Oregon) is 18.7 cubic kilometers (from Wikipedia - numbers vary slightly between sources). The volume of a diet coke can is 12 fluid ounces, which is 354.88 milliliters. Dividing these gives 5.27E13 True Answer: 13
If you used a single standard size #2 pencil to draw a line (assuming an infinite amount of standard printer paper), and used up the pencil entirely, how many times could that line cross the English channel (at the channel's narrowest point)?
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Re: Fermi Questions C

Postby talkingturtle101 » June 23rd, 2017, 1:18 pm

My Answer
- I remember reading somewhere that you could draw a line for 40 miles-ish with one pencil. - The English Channel might be 20 miles wide at its narrowest. So dividing gives 2, Fermi Answer of 0?
Actual Answer
- Google says you could draw a line for 35 miles. - At it's narrowest, it's 20.9 miles. - So Fermi Answer of 0
Sticking with the topic of bodies of water, how many dictionaries do you need to print out to have the amount of ink used to be equal to the volume of the Pacific Ocean?
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Re: Fermi Questions C

Postby Unome » June 23rd, 2017, 2:09 pm

Depends which dictionary
- Most printers print somewhere in the range of E2-E3 pages on one cartridge, so I'll go with 5E2. - A cartiridge is like 5E1 mL, dividing gives E1 pages per mL. I'll underestimate for simplicity and say it's E-1 dictionaries per mL. - The Earth is ~E4 km radius, so ~ 4E8 km^2 surface area (can't remember the exact formula sadly), ~E8 km^2 Pacific Ocean, ~E18 cm^2. - The depth is ~E1 km so ~E6 cm. Multiplying gives E24 mL of water. I should really memorize the volume of the Pacific Ocean at some point. E24 mL multiplied by E-1 dictionaries per mL gives E23 dictionaries. Fermi Answer: 23
Actual Answer
- It appears that the ratio is 2E1 pages per mL of ink. Sicne you didn't specify I'll assume a dictionary size of 1000 pages - this gives 2E-2 dictionaries per mL. - The volume of the Pacific Ocean is around 7.1E23 mL. - Multiplying gives 1.42E22. Fermi Answer: 22
How many times could a full Boeing 747 fly around the Earth if it had begun when the Earth was formed? Assume infinite fuel, continuous top speed, and an atmosphere identical to the present one.
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Re: Fermi Questions C

Postby talkingturtle101 » June 24th, 2017, 2:25 pm

Nice Question
- Earth formed 4.6 billion years ago, or 5E9 - It could probably go 1000 kph, or 1E3. - The Earth is around 40000 km in circumference, because light can go around it 7 times per second. This is 4E4. - There's around 8,000 hours in a year, so the earth is 4E13 hours old. - So it would take 40 hours for a 747 to go around the Earth once, or 4E1. - Dividing gives a nice Fermi Answer of 12.
Actual Answer
- The Earth formed 4.03 E13 hours ago. - Top speed of a 747 is 9.2 E2 kilometers per hour. - Earth is almost exactly 40,000 km in circumference, or 4 E4. - So it would take 43.48 hours for a 747 to go around the Earth once. - Dividing 4.03 E13 by 43.48 gives us 9.27 E11, which gives us - Fermi Answer of 12
How many pages could a standard printer print off if it started printing when the universe formed? Assume infinite ink.
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