N times log(n minus n times .43429(log of e) plus one works well, especially with higher numbersUnome wrote:That seems to be a really good approximation... but how are you supposed to use that practically?jonboyage wrote:I looked it up recently and Stirling’s Approximation seems to be good:Unome wrote:Does anyone know any good ways to do factorials? I've been having problems estimating them, and memorization isn't helping.
Edit: it should be plus log(sqrt of n but it'll usually be 1 anyways