Fermi Questions C

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Re: Fermi Questions C

Postby Name » May 4th, 2018, 9:14 pm


The question specifically asked for percentage. According to Google it's 1/3,748,067 or about 3E-7 not E-5 (though sources do change I don't realistically think it's as high as E-5).
oh darn...

Edit:
How many more people are diagnosed with esophageal cancer each year in the US than are diagnosed with mesothelioma?
attempt
Both seem to types of cancers, (-oma signifies cancer) but since I haven't heard of mesothelioma, I would say its rarer. I would think that not more than e5 people are diagnosed with esophageal cancer in the US per year because any higher and you get a significant portion of the population. And I wouldn't think that this other type of cancer occurs less than e3 to e4 types per year. I feel like my initial e5 for esophageal cancer was a bit high, so I'm going to choose [b]1[/b] instead of 2 as my final answer.
Actual
200,000 people are diagnosed by esophageal cancer in the US annually, and 20,000 with mesothelioma which works out rather smoothly, to a fermi answer of [b]1[/b]
I don't know if you'll be able to verify an answer to this question later, but here goes anyways:
If I had as many copies of the Beowulf, Heaney translation, as would be as long as all the forums posts made on this website since 2008, how much would they weigh? (assume all the books are paperback)
The question asks for how many more, not how many times more, indicating subtraction. 180,000 or E5

Also could you clarify the question? Like a copy for any post? Every page? Every thread?
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Re: Fermi Questions C

Postby PM2017 » May 4th, 2018, 9:18 pm

oh darn...

Edit:
attempt
Both seem to types of cancers, (-oma signifies cancer) but since I haven't heard of mesothelioma, I would say its rarer. I would think that not more than e5 people are diagnosed with esophageal cancer in the US per year because any higher and you get a significant portion of the population. And I wouldn't think that this other type of cancer occurs less than e3 to e4 types per year. I feel like my initial e5 for esophageal cancer was a bit high, so I'm going to choose [b]1[/b] instead of 2 as my final answer.
Actual
200,000 people are diagnosed by esophageal cancer in the US annually, and 20,000 with mesothelioma which works out rather smoothly, to a fermi answer of [b]1[/b]
I don't know if you'll be able to verify an answer to this question later, but here goes anyways:
If I had as many copies of the Beowulf, Heaney translation, as would be as long as all the forums posts made on this website since 2008, how much would they weigh? (assume all the books are paperback)
The question asks for how many more, not how many times more, indicating subtraction. 180,000 or E5

Also could you clarify the question? Like a copy for any post? Every page? Every thread?
Ah, I'm used to how many more being how many more as a factor, sorry.

Also, think of it as one copy = however many posts have as many words as one copy of the book.
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Re: Fermi Questions C

Postby UTF-8 U+6211 U+662F » May 9th, 2018, 1:27 pm

attempt
Both seem to types of cancers, (-oma signifies cancer) but since I haven't heard of mesothelioma, I would say its rarer. I would think that not more than e5 people are diagnosed with esophageal cancer in the US per year because any higher and you get a significant portion of the population. And I wouldn't think that this other type of cancer occurs less than e3 to e4 types per year. I feel like my initial e5 for esophageal cancer was a bit high, so I'm going to choose [b]1[/b] instead of 2 as my final answer.
Actual
200,000 people are diagnosed by esophageal cancer in the US annually, and 20,000 with mesothelioma which works out rather smoothly, to a fermi answer of [b]1[/b]
I don't know if you'll be able to verify an answer to this question later, but here goes anyways:
If I had as many copies of the Beowulf, Heaney translation, as would be as long as all the forums posts made on this website since 2008, how much would they weigh? (assume all the books are paperback)
The question asks for how many more, not how many times more, indicating subtraction. 180,000 or E5

Also could you clarify the question? Like a copy for any post? Every page? Every thread?
Ah, I'm used to how many more being how many more as a factor, sorry.

Also, think of it as one copy = however many posts have as many words as one copy of the book.
Attempt
There's maybe 5 posts per active person every day, with maybe 50 active people for every day, giving 250 posts per day * 365 days per year * 10 years = 9E5 posts. With an average of 100 words/post, that gives 9E7 words. One copy of Beowulf has maybe 100 words per page and 400 pages, giving 4E4 copies of Beowulf. They all weigh at most three kilograms, which gives a Fermi answer of 5 (in kilograms).
Not sure how I would check this one..

Give the distance from Earth to Alpha Centauri in terms of the distance traveled by A4 paper undergoing free fall for 10 hours.

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Re: Fermi Questions C

Postby sciencegirl03 » May 11th, 2018, 8:09 pm

Distance to Alpha Centauri: 4.5light years; i.e. 4.5 * 10^16m\
Paper falls at 1m/sec so in 10 hrs= 36000meters
Fermi answer 11
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Re: Fermi Questions C

Postby Name » May 11th, 2018, 8:18 pm

Distance to Alpha Centauri: 4.5light years; i.e. 4.5 * 10^16m\
Paper falls at 1m/sec so in 10 hrs= 36000meters
Fermi answer 11
Free fall implies acceleration not a constant velocity. Also try to write a attempt and a solution with the hide option in formatting. Also put a question after the answers.
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Re: Fermi Questions C

Postby UTF-8 U+6211 U+662F » May 11th, 2018, 8:34 pm

I just realized I meant fall at terminal velocity, but it doesn't really make the question invalid, so I'll stick with free fall.
Actual answer
Paper would travel, in 10 hrs, 4.9 m/s^2 * (10 hrs * 3600 s/hrs)^2, which is 6.35E9 meters. The distance to Alpha Centauri is 4.132E16 meters, giving a Fermi answer of 7.
(I think I did that right: I'm new to this)

Someone else can ask a question.

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Re: Fermi Questions C

Postby sciencegirl03 » May 11th, 2018, 8:39 pm

Distance to Alpha Centauri: 4.5light years; i.e. 4.5 * 10^16m\
Paper falls at 1m/sec so in 10 hrs= 36000meters
Fermi answer 11
Sorry, no drag....
Distance to Alpha Centauri: 4.5light years; i.e. 4.5 * 10^16m
Distance paper falls: .5 * 10 * 36000^2 = 6.5 * 10^9m
Fermi answer: 7

Still figuring out the Attempt/Hide...
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Re: Fermi Questions C

Postby UTF-8 U+6211 U+662F » May 11th, 2018, 8:41 pm

Still figuring out the Attempt/Hide...
Use

Code: Select all

[hide]Attempt|adfjsakdjfksajdfkj[/hide]
for the attempt and either

Code: Select all

[hide]Answer|asdkfjakdsjfksj[/hide]
or

Code: Select all

[answer]aksdjfkasjdfkajf[/answer]
for the answer.
The vertical bar is right above the enter button on my QWERTY keyboard.

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Re: Fermi Questions C

Postby sciencegirl03 » May 11th, 2018, 9:19 pm

Still figuring out the Attempt/Hide...
Use

Code: Select all

[hide]Attempt|adfjsakdjfksajdfkj[/hide]
for the attempt and either

Code: Select all

[hide]Answer|asdkfjakdsjfksj[/hide]
or

Code: Select all

[answer]aksdjfkasjdfkajf[/answer]
for the answer.
The vertical bar is right above the enter button on my QWERTY keyboard.
Thanks UTF-8 U+6211 U+662F
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Re: Fermi Questions C

Postby NeilMehta » May 14th, 2018, 6:18 am

New question:
On average, how many text messages are sent every nanosecond?
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Re: Fermi Questions C

Postby Unome » May 14th, 2018, 7:08 am

Attempt
Approximately 1E12 text messages per year, divide by 3E7 to get to seconds, divide by 1E9 to get to nanoseconds, yields 3E-5 so Fermi Answer: -5
Actual
8.6E12 text messages per year, arund 2.7E-4 per nanosecond, so Fermi Answer: -4
How much energy in ergs is transferred to the Earth by the moon reflecting sunlight over the course of one Svedberg?
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Re: Fermi Questions C

Postby Name » May 14th, 2018, 7:31 am

Attempt
The surface area of the moon is around 3E7. Distance to sun E8 so surface area is around 2E17. 3E7/2E17 is 1.5E-10 times 4E26 is 6E16. Distance to moon E5 or about 2E11 surface area. Surface area of earth 5E8/2E11 is 2.5E-3 times 6E16 is 1.5E14 Assuming a 1 percent reflection 1.5E12joules/sec. One svedberg is E-13 one erg is E-7. So 1.5E6 or Fermi 6
Answer
energy reflection is around 10 percent but the distance to moon is 3E5 not E5 and would cancel out each other so E6
Assuming a uniform density of earth how many times stronger is Earth's gravitational force at it's surface compared to if you went underground 1000 kilometers
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Re: Fermi Questions C

Postby PM2017 » May 14th, 2018, 7:41 am

Attempt
The surface area of the moon is around 3E7. Distance to sun E8 so surface area is around 2E17. 3E7/2E17 is 1.5E-10 times 4E26 is 6E16. Distance to moon E5 or about 2E11 surface area. Surface area of earth 5E8/2E11 is 2.5E-3 times 6E16 is 1.5E14 Assuming a 1 percent reflection 1.5E12joules/sec. One svedberg is E-13 one erg is E-7. So 1.5E6 or Fermi 6
Answer
energy reflection is around 10 percent but the distance to moon is 3E5 not E5 and would cancel out each other so E6
Assuming a uniform density of earth how many times stronger is Earth's gravitational force at it's surface compared to if you went underground 1000 kilometers
attempt
well, the Earth has a radius of 1100 km iirc, so the new distance is 1000, for a ratio of 10000/11000, or 10/11. Squaring this is still very close to one (1/1.21) so Fermi answer 0.
I'll add the actual once I can get to my laptop.

What is the 273rd Fibonacci number?
To clarify, 0 will be considered the first Fibonacci number.
Last edited by PM2017 on May 14th, 2018, 10:25 am, edited 1 time in total.
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Re: Fermi Questions C

Postby Name » May 14th, 2018, 8:28 am

Attempt
The surface area of the moon is around 3E7. Distance to sun E8 so surface area is around 2E17. 3E7/2E17 is 1.5E-10 times 4E26 is 6E16. Distance to moon E5 or about 2E11 surface area. Surface area of earth 5E8/2E11 is 2.5E-3 times 6E16 is 1.5E14 Assuming a 1 percent reflection 1.5E12joules/sec. One svedberg is E-13 one erg is E-7. So 1.5E6 or Fermi 6
Answer
energy reflection is around 10 percent but the distance to moon is 3E5 not E5 and would cancel out each other so E6
Assuming a uniform density of earth how many times stronger is Earth's gravitational force at it's surface compared to if you went underground 1000 kilometers
attempt
well, the Earth has a radius of 1100 km iirc, so the new distance is 1000, for a ratio of 10000/11000, or 10/11. Squaring this is still very close to one (1/1.21) so Fermi answer 0.
I'll add the actual once I can get to my laptop.

What is the 273rd Fibonacci number?
Wait a screwed up the question. It is E0 but I should've said something like 3000 where the new mass is around E22 and radius is 1000 where the gravitational force is E1 stronger while on the surface
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Re: Fermi Questions C

Postby Tom_MS » May 14th, 2018, 10:55 am

Wait a screwed up the question. It is E0 but I should've said something like 3000 where the new mass is around E22 and radius is 1000 where the gravitational force is E1 stronger while on the surface
I feel like this is being overthought. According to the shell theorem (essentially Gauss's law), the only mass that matters should be within a spherical shell at the radius being considered. If you do the math, this gives a linearly decreasing force for a linearly decreasing radius. Thus, just taking the ratio of 5/6 (5000 km compared to around 6000 km) gives you fermi 0.


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