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### Re: Fermi Questions C

Posted: May 14th, 2018, 11:38 am
According to the shell theorem (essentially Gauss's law), the only mass that matters should be within a spherical shell at the radius being considered.
Vector calculus being useful XD

### Re: Fermi Questions C

Posted: May 14th, 2018, 11:44 am
Wait a screwed up the question. It is E0 but I should've said something like 3000 where the new mass is around E22 and radius is 1000 where the gravitational force is E1 stronger while on the surface
I feel like this is being overthought. According to the shell theorem (essentially Gauss's law), the only mass that matters should be within a spherical shell at the radius being considered. If you do the math, this gives a linearly decreasing force for a linearly decreasing radius. Thus, just taking the ratio of 5/6 (5000 km compared to around 6000 km) gives you fermi 0.
Wait hmm I checked the math and this seems correct. I probably screwed up something while doing the math earlier. The mass is porportional to volume which is radius cubed and is divided by radius squared so the force is linearly decreasing.

### Re: Fermi Questions C

Posted: May 15th, 2018, 4:22 am
What is the 273rd Fibonacci number?
To clarify, 0 will be considered the first Fibonacci number.
`Using an approximation which I will not disclose, it's RIGHT on the edge between 56 and 57, but I'll say 57.`
`Using an online calculator, the 273rd Fibonacci number is 5.06*10^56, so yes. Barely 57. Bwahahaha.`
A proton and electron are initially separated by 1 meter. After being released, they end up colliding due to their coulombic attraction. If the final kinetic energy (right before collision) of the two particles is converted almost entirely into rest mass energy of the particles released, how much mass is formed (kg)?

### Re: Fermi Questions C

Posted: May 15th, 2018, 6:25 am
Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)

### Re: Fermi Questions C

Posted: May 15th, 2018, 7:07 am
Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)
Uh it's pretty easy to just google

### Re: Fermi Questions C

Posted: May 15th, 2018, 7:15 pm
Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)
Uh it's pretty easy to just google
It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.

### Re: Fermi Questions C

Posted: May 15th, 2018, 7:21 pm
Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)
Uh it's pretty easy to just google
It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.
Wait I was thinking of something else... The limit of the ratio between one Fibonacci number and the next is the golden ratio, as you get larger and larger numbers. So you just do (Phi)^(273-1).

### Re: Fermi Questions C

Posted: May 15th, 2018, 7:23 pm

Uh it's pretty easy to just google
It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.
Wait I was thinking of something else... The limit of the ratio between one Fibonacci number and the next is the golden ratio, as you get larger and larger numbers. So you just do (Phi)^(273-1).
This is how I would do it.

### Re: Fermi Questions C

Posted: May 15th, 2018, 8:30 pm
It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.
Wait I was thinking of something else... The limit of the ratio between one Fibonacci number and the next is the golden ratio, as you get larger and larger numbers. So you just do (Phi)^(273-1).
This is how I would do it.
Oops I appear to have read "fibonacci" as "factorial"

Yes, this seems to be the ideal way of doing it.

### Re: Fermi Questions C

Posted: May 28th, 2018, 6:34 pm
Time to restart this thread for now... b/c it'll be relevant next year!

With the hot air coming out of Donald Trump's mouth when he says cofveve, how many times would he need to repeat it in order to boil water? Whoever actually solves this (not you whythelongface) correctly gets a cookie!