Fermi Questions C

Test your knowledge of various Science Olympiad events.
User avatar
NeilMehta
WikiMod
WikiMod
Posts: 318
Joined: August 27th, 2016, 5:27 am
Division: C
State: NY

Re: Fermi Questions C

Postby NeilMehta » February 12th, 2018, 4:33 pm

Unome wrote:How much is the mass of all the live rhinoviruses in the world in units of the mass of a standard No. 2 wooden pencil?

Attempt
Honestly, no idea how to approach this one.. let's say the mass of one rhinovirus is E-12 g?
In that case, E13 rhinoviruses would weight the same a pencil. Guessing that there are E14 rhinoviruses, final answer of 1

Solution
So after doing some research, I can't find any information on the number of rhinoviruses out there, or the mass of one, but at least i got the mass of a pencil right :P

New question: how many turkeys would it take to feed the entire country of Turkey for the next 100 years?
i can't feel my arms wtf i think i'm turning into a lamp

voted least likely to sleep 2018, most likely to sleep in class 2017+2018, biggest procrastinator 2018

User avatar
Riptide
Exalted Member
Exalted Member
Posts: 186
Joined: December 4th, 2017, 7:09 pm
Division: Grad
State: TX
Contact:

Re: Fermi Questions C

Postby Riptide » February 12th, 2018, 4:59 pm

NeilMehta wrote:New question: how many turkeys would it take to feed the entire country of Turkey for the next 100 years?


Attempt
Not too sure about this but I’ll assume a population of 7 in Turkey. One turkey could probably last one person a few days(if you eat relatively minimally). This means each person would need 4 turkeys in a hundred years, which gives an answer of 11.


Actual
The population of Turkey is 80 million and it looks like one turkey has 20,000 kJ of energy. Each person needs an average 8,700 kJ of energy a day, so each person needs 16,000 turkeys in 100 years. This results in an answer of 12.


How many humans have ever lived?
University of California at Berkeley '23
Seven Lakes High School '19
Seven Lakes Junior High '15

User avatar
Name
Member
Member
Posts: 275
Joined: January 21st, 2018, 4:41 pm
Division: C
State: NY
Location: Syosset

Re: Fermi Questions C

Postby Name » February 12th, 2018, 5:42 pm

Riptide wrote:
NeilMehta wrote:New question: how many turkeys would it take to feed the entire country of Turkey for the next 100 years?


Attempt
Not too sure about this but I’ll assume a population of 7 in Turkey. One turkey could probably last one person a few days(if you eat relatively minimally). This means each person would need 4 turkeys in a hundred years, which gives an answer of 11.


Actual
The population of Turkey is 80 million and it looks like one turkey has 20,000 kJ of energy. Each person needs an average 8,700 kJ of energy a day, so each person needs 16,000 turkeys in 100 years. This results in an answer of 12.


How many humans have ever lived?

Attempt
I believe about 100 billion people have ever lived or 11.

Actual
Around 108 billion so 11


Question: How much energy (in joules) is an Einstein of infared light (Edit: infared light varies so wavelength of 1 mcm)
South Woods MS (5 medals)/Syosset HS (24 medals)
Favorite Past Events: Microbe, Invasive, Matsci, Fermi
Next Year: Astro, Code, hopefully Orni, and maybe Compound
2018-19 highlights
mit- 1st code, 3rd fermi
cornell- 1st fermi
states- 1st fermi, 3rd astro, 3rd code
19 medals

User avatar
PM2017
Member
Member
Posts: 483
Joined: January 20th, 2017, 5:02 pm
Division: Grad
State: CA

Re: Fermi Questions C

Postby PM2017 » February 12th, 2018, 6:43 pm

Name wrote:
Riptide wrote:
NeilMehta wrote:New question: how many turkeys would it take to feed the entire country of Turkey for the next 100 years?


Attempt
Not too sure about this but I’ll assume a population of 7 in Turkey. One turkey could probably last one person a few days(if you eat relatively minimally). This means each person would need 4 turkeys in a hundred years, which gives an answer of 11.


Actual
The population of Turkey is 80 million and it looks like one turkey has 20,000 kJ of energy. Each person needs an average 8,700 kJ of energy a day, so each person needs 16,000 turkeys in 100 years. This results in an answer of 12.


How many humans have ever lived?

Attempt
I believe about 100 billion people have ever lived or 11.

Actual
Around 108 billion so 11


Question: How much energy (in joules) is an Einstein of infared light (Edit: infared light varies so wavelength of 1 mcm)



Attempt
ir light is like 1000 nm so 1mcm. e = hc/lambda, h is -33, c is 8, and lambda here is -6. so e = -33+8-(-6) = -19. Then, add 24 to get 5.


Actual
e(per photon) = hc/lambda. h is 6.626e-34J*s, c is 3e8m, lambda is 10e-6m. Multiply them together and you get 1.88e-19J(per photon). Then multiply by avogadro's number (6.022e23) to get 113,000 J(/mole), which is 5


EDIT: I forgot to post a question. Give me one second while I come up with something
2018 Events
Astronomy, Mousetrap Vehicle, Mission Possible, Fermi Questions

2019 Events
Astronomy, Mousetrap Vehicle, Mission Possible, Fermi Questions :cry: , Circuit Lab

--
West High '19
UC Berkeley '23

User avatar
PM2017
Member
Member
Posts: 483
Joined: January 20th, 2017, 5:02 pm
Division: Grad
State: CA

Re: Fermi Questions C

Postby PM2017 » February 12th, 2018, 7:01 pm

PM2017 wrote:
Name wrote:
Riptide wrote:
Attempt
Not too sure about this but I’ll assume a population of 7 in Turkey. One turkey could probably last one person a few days(if you eat relatively minimally). This means each person would need 4 turkeys in a hundred years, which gives an answer of 11.


Actual
The population of Turkey is 80 million and it looks like one turkey has 20,000 kJ of energy. Each person needs an average 8,700 kJ of energy a day, so each person needs 16,000 turkeys in 100 years. This results in an answer of 12.


How many humans have ever lived?

Attempt
I believe about 100 billion people have ever lived or 11.

Actual
Around 108 billion so 11


Question: How much energy (in joules) is an Einstein of infared light (Edit: infared light varies so wavelength of 1 mcm)



Attempt
ir light is like 1000 nm so 1mcm. e = hc/lambda, h is -33, c is 8, and lambda here is -6. so e = -33+8-(-6) = -19. Then, add 24 to get 5.


Actual
e(per photon) = hc/lambda. h is 6.626e-34J*s, c is 3e8m, lambda is 10e-6m. Multiply them together and you get 1.88e-19J(per photon). Then multiply by avogadro's number (6.022e23) to get 113,000 J(/mole), which is 5


EDIT: I forgot to post a question. Give me one second while I come up with something


If I was 250 pounds and walked nonstop, but still consumed 2500 Calories daily, how much time would it take to reach 100 pounds, in terms of the lifetime of a 100 solar mass star?
2018 Events
Astronomy, Mousetrap Vehicle, Mission Possible, Fermi Questions

2019 Events
Astronomy, Mousetrap Vehicle, Mission Possible, Fermi Questions :cry: , Circuit Lab

--
West High '19
UC Berkeley '23

User avatar
Riptide
Exalted Member
Exalted Member
Posts: 186
Joined: December 4th, 2017, 7:09 pm
Division: Grad
State: TX
Contact:

Re: Fermi Questions C

Postby Riptide » February 12th, 2018, 7:42 pm

PM2017 wrote:If I was 250 pounds and walked nonstop, but still consumed 2500 Calories daily, how much time would it take to reach 100 pounds, in terms of the lifetime of a 100 solar mass star?

Attempt
This is a pretty interesting question. I think you burn around 500 calories an hour walking, so that’s a net decrease of around E4 calories a day. Let’s assume E3 calories is 1 pound. This means it will take E5 days to burn off 150 pounds. I don’t know much about Astro, but I’m fairly confident the suns lifetime is E10 years, so I’ll assume a star 100x that will have a lifetime of E8 years. This gives a final answer of -5.

Actual
I found some contrasting information, but it looks like you would burn around 300 calories an hour walking if you are 250 pounds. This amount would change as you decrease your weight while walking, but just to keep it simple I'll assume a steady rate of 300 calories an hour. The net loss of calories is 4700 calories a day. 1 pound is equal to 3500 calories, so 150 pounds would take 525,000 calories to burn. It would take 111 days to burn off 150 pounds for walking nonstop. I couldn't find the lifespan of a 100 solar mass star, but according to a friend that does Astro it'd be around E6 years (idk how accurate that is). This gives a final answer of -7 (I feel like this could be completely off so someone correct me if you see any errors please)
Edit: Someone else just told me that it is E5 years, so the answer would change to -6

If for every Apple user in the world I had 84,000 nickels and 750,000 yen, how much money would I have in total in Hryvnia (currency of Ukraine)?
Last edited by Riptide on February 12th, 2018, 8:15 pm, edited 1 time in total.
University of California at Berkeley '23
Seven Lakes High School '19
Seven Lakes Junior High '15

Justin72835
Member
Member
Posts: 170
Joined: June 25th, 2017, 7:06 am
Division: C
State: TX

Re: Fermi Questions C

Postby Justin72835 » February 12th, 2018, 7:58 pm

Riptide wrote:If for every Apple user in the world I had 84,000 nickels and 750,000 yen, how much money would I have in total in Hryvnia (currency of Ukraine)?

My Answer
I'm going to estimate that there are 1e9 Apple users.
84,000 nickels = $4,200 and 750,000 yen = about $7500, so everybody gets around $1e4
This equates to $1e12 for the money held by all the Apple users.
Idk the conversion rate between Hryvnia and US dollars so I'll assume that its around 1e3 per dollar, which gives an answer of 1e15.

Fermi Answer: 15

Correct Answer
588 million Apple users
84,000 nickels and 750,000 yen actually equates to $11,100.
The actual conversion rate is 27:1 RIP.
By equating everything you get an answer of 1.8e14.

Fermi Answer: 14

If you were to take all the water in Lake Michigan and set it over a regular campfire, how long would it take for the entire volume of water to change by 1 degree Celcius in seconds (assume that the water is heated equally throughout its volume)?
Last edited by Justin72835 on February 12th, 2018, 8:06 pm, edited 3 times in total.
"The fault, dear Brutus, is not in our stars,
But in ourselves, that we are underlings."


Seven Lakes High School '19

User avatar
PM2017
Member
Member
Posts: 483
Joined: January 20th, 2017, 5:02 pm
Division: Grad
State: CA

Re: Fermi Questions C

Postby PM2017 » February 12th, 2018, 8:03 pm

Riptide wrote:
PM2017 wrote:If I was 250 pounds and walked nonstop, but still consumed 2500 Calories daily, how much time would it take to reach 100 pounds, in terms of the lifetime of a 100 solar mass star?

Attempt
This is a pretty interesting question. I think you burn around 500 calories an hour walking, so that’s a net decrease of around E4 calories a day. Let’s assume E3 calories is 1 pound. This means it will take E5 days to burn off 150 pounds. I don’t know much about Astro, but I’m fairly confident the suns lifetime is E10 years, so I’ll assume a star 100x that will have a lifetime of E8 years. This gives a final answer of -5.

Actual
I found some contrasting information, but it looks like you would burn around 300 calories an hour walking if you are 250 pounds. This amount would change as you decrease your weight while walking, but just to keep it simple I'll assume a steady rate of 300 calories an hour. The net loss of calories is 4700 calories a day. 1 pound is equal to 3500 calories, so 150 pounds would take 525,000 calories to burn. It would take 111 days to burn off 150 pounds for walking nonstop. I couldn't find the lifespan of a 100 solar mass star, but according to a friend that does Astro it'd be around E6 years (idk how accurate that is). This gives a final answer of -7 (I feel like this could be completely off so someone correct me if you see any errors please)
Edit: Someone else just told me that it is E7 years, so the answer would change to -8

If for every Apple user in the world I had 84,000 nickels and 750,000 yen, how much money would I have in total in Hryvnia (currency of Ukraine)?


Attempt
Converting to dollars: 84,000/20 = 4200, I'll assume a yen is OoM less than a dollar so 75,000 dollars, for a total of 79,200 dollars. I'd guess (without any reason, other than that a dollar has sooooo much value compared to most currencies, and I hadn't hear of a Hryvnia before) that a Hryvnia is also one OoM less than a dollar, so 792,000 Hryvnia, or 6. I'd say there's 9 apple users, bringing this up to 15


Actual
Converting to dollars: 84,000/20 = 4200, A yen is 0.0092 dollars, so 750,000 yen = 6900 dollars (I'm surprised at this given how advanced a nation Japan is.) This brings the total up to 11,100 dollars. A hryvnia is 0.037 dollars, so a dollar is (1/0.037) Hryvnia = 27.03 Hryvnia. 11,100*27.03 = 300,033 Hryvnia. Then, times 588 million users, so 1.8e+14, so the answer is 14. (close enough I guess.)


Thanks for reminding me to add currency valuation to my fermi value sheet.

Question:

How many medals are won in Science Olympiad each season?




EDIT: RIPPPPPP, the user above me answered while I was typing this post. I guess the next person has to answer both questions or just choose lol
2018 Events
Astronomy, Mousetrap Vehicle, Mission Possible, Fermi Questions

2019 Events
Astronomy, Mousetrap Vehicle, Mission Possible, Fermi Questions :cry: , Circuit Lab

--
West High '19
UC Berkeley '23

Justin72835
Member
Member
Posts: 170
Joined: June 25th, 2017, 7:06 am
Division: C
State: TX

Re: Fermi Questions C

Postby Justin72835 » February 12th, 2018, 8:08 pm

<deleted>
Last edited by Justin72835 on February 12th, 2018, 8:12 pm, edited 1 time in total.
"The fault, dear Brutus, is not in our stars,
But in ourselves, that we are underlings."


Seven Lakes High School '19

User avatar
Name
Member
Member
Posts: 275
Joined: January 21st, 2018, 4:41 pm
Division: C
State: NY
Location: Syosset

Re: Fermi Questions C

Postby Name » February 12th, 2018, 8:11 pm

Justin72835 wrote:
My Answer
I'm going to estimate that there are 1e9 Apple users.
84,000 nickels = $4,200 and 750,000 yen = about $7500, so everybody gets around $1e4
This equates to $1e12 for the money held by all the Apple users.
Idk the conversion rate between Hryvnia and US dollars so I'll assume that its around 1e3 per dollar, which gives an answer of 1e15.

Fermi Answer: 15

Correct Answer
588 million Apple users
84,000 nickels and 750,000 yen actually equates to $111,000.
The actual conversion rate is 27:1 RIP.
By equating everything you get an answer of 1.8e14.

Fermi Answer: 14

If you were to take all the water in Lake Michigan and set it over a regular campfire, how long would it take for the entire volume of water to change by 1 degree Celcius in seconds (assume that the water is heated equally throughout its volume)?

Attempt
Assume volume is around 3 km so 18 cm. Assuming energy from a campfire/ sec is 6 cal per sec so 12

Answer
Volume is correct. I can't find anything about energy from a fire but should be within 1

What is (plancks constant divided by Boltzmann's constant divided by avagados constant divided by gravitational constant divided by the elementary charge divided by speed of light)^2
Bonus: 1,000,000!
Edit: Scioly medals probably around 200 invites 6 medal per event, 47 medals (23 event 2 each 1 extra for ExDes) or 4E4 plus regionals/states/nats so probably 5
Edit 2: Actually not everywhere is like NY with most competitions having 6-10 medals so actually probably 4
Last edited by Name on February 12th, 2018, 8:21 pm, edited 2 times in total.
South Woods MS (5 medals)/Syosset HS (24 medals)
Favorite Past Events: Microbe, Invasive, Matsci, Fermi
Next Year: Astro, Code, hopefully Orni, and maybe Compound
2018-19 highlights
mit- 1st code, 3rd fermi
cornell- 1st fermi
states- 1st fermi, 3rd astro, 3rd code
19 medals

User avatar
Riptide
Exalted Member
Exalted Member
Posts: 186
Joined: December 4th, 2017, 7:09 pm
Division: Grad
State: TX
Contact:

Re: Fermi Questions C

Postby Riptide » February 12th, 2018, 8:14 pm

PM2017 wrote:How many medals are won in Science Olympiad each season?

Attempt
Assuming all 50 states participate in scioly, medals are on average given out to top 4 placings (often varies from 3 to 6 but 4 seems pretty average to me). 2 divisions, 23 events each, 184 medals per tournament. Let's assume 10 invitationals, 6 regionals, and obviously 1 state tournament. This gives us 3 medals won each season per state, so 5 total.

Not exactly sure where to find this information, so I'll let PM2017 give us the answer.

Since someone else just posted, check the post above for the newest question (Don't want to create 2 strands of questions lol)
University of California at Berkeley '23
Seven Lakes High School '19
Seven Lakes Junior High '15

Raleway
Exalted Member
Exalted Member
Posts: 228
Joined: March 12th, 2017, 7:19 pm
Division: C
State: -

Re: Fermi Questions C

Postby Raleway » February 12th, 2018, 11:00 pm

Time to waltz into the realm of craziness too late at night: Amount of individual pasta noodles created each year divided by the amount of energy in joules that the entire universe consumes each year, added on by the total area of the LOL map in DPI units.
Sleep is for the week; one only needs it once a week :!: :geek: :roll: :?: :idea:

God bless Len Joeris | Balsaman

User avatar
Unome
Moderator
Moderator
Posts: 4043
Joined: January 26th, 2014, 12:48 pm
Division: Grad
State: GA
Location: somewhere in the sciolyverse

Re: Fermi Questions C

Postby Unome » February 14th, 2018, 5:17 am

Attempt
Estimating E13 pasta noodles per year. Energy the universe consumes doesn't seem to make sense to me as a concept, but I'll go with E70 Joules. The map area is probably about E8; being a MOBA I assume the map isn't that huge. Ultimately the latter is the only thing that's relevant due to it be added - hence Fermi Answer: 8

Actual
The question doesn't actually make sense, since you can't exactly render a digital game map in DPI. The answer is probably in the range of E6-E8 though, since the energy in the universe is very high.

How many M&Ms are consumed each year by the number of people that could fill the stands of Wright State University's Nutter Center?
Userpage
Chattahoochee High School Class of 2018
Georgia Tech Class of 2022

Opinions expressed on this site are not official; the only place for official rules changes and FAQs is soinc.org.

User avatar
Riptide
Exalted Member
Exalted Member
Posts: 186
Joined: December 4th, 2017, 7:09 pm
Division: Grad
State: TX
Contact:

Re: Fermi Questions C

Postby Riptide » February 14th, 2018, 9:51 am

Unome wrote:How many M&Ms are consumed each year by the number of people that could fill the stands of Wright State University's Nutter Center?

Attempt
Not exactly sure but I'll just assume around 20,000 for the capacity of the Nutter Center. I don't think that many M&M's are eaten by a single person, so I'll assume around 5 packets a year? Around 20 pieces of M&M's per packet would gives us gives us 100 M&M's per person, so E6 total.

Actual
The Nutter Center can hold 10,400 people. Can't find how many are eaten by one person a year, but there are 400,000,000 produced each day, so 1.46E9 M&M's produced each year. Divide that by the world population gives us 19 M&M's a year per person. 10,400*19 gives us a final answer of E5.

What is the number of people over the age of 90 in the world divided by the number of children under the age of 15 in Australia?
University of California at Berkeley '23
Seven Lakes High School '19
Seven Lakes Junior High '15

User avatar
Unome
Moderator
Moderator
Posts: 4043
Joined: January 26th, 2014, 12:48 pm
Division: Grad
State: GA
Location: somewhere in the sciolyverse

Re: Fermi Questions C

Postby Unome » February 14th, 2018, 11:02 am

Attempt
7E9 people worldwide, about 1.5E-3 proportion are over 90 years old - therefore, E7 people worldwide over age 90. The population of Australia is in the range of 8E7, approximately 1/6 are under age 15 so around E7. Fermi Answer: 0

Actual
It's hard to find good data, but according to population pyramids approximately 20 million people worldwide are over the age of 90 - 2E7. 18% of Australia is under age 15, but I overestimated; the total population of Australia is around 25 million - hence, 4.4E6 people.
Dividing yields Fermi Answer: 1

How many times have AK-47s been fired in the entirety of human history through the end of 2016? (i.e. total number of shots)
Userpage
Chattahoochee High School Class of 2018
Georgia Tech Class of 2022

Opinions expressed on this site are not official; the only place for official rules changes and FAQs is soinc.org.


Return to “2018 Question Marathons”

Who is online

Users browsing this forum: No registered users and 1 guest