Thermodynamics B/C

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Re: Thermodynamics B/C

Post by MattChina » April 4th, 2018, 7:05 am

Justin72835 wrote:Two gases occupy two containers, A and B. The gas in A, of volume 0.14 cubic meters, exerts a pressure of 1.18 MPa. The gas in B, of volume 0.21 cubic meters, exerts a pressure of 0.82 MPa. The containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant?
0.964?
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Re: Thermodynamics B/C

Post by Justin72835 » April 4th, 2018, 6:51 pm

MattChina wrote:
Justin72835 wrote:Two gases occupy two containers, A and B. The gas in A, of volume 0.14 cubic meters, exerts a pressure of 1.18 MPa. The gas in B, of volume 0.21 cubic meters, exerts a pressure of 0.82 MPa. The containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant?
0.964?
Not quite. How did you get your answer?

EDIT: This answer is actually correct.
Last edited by Justin72835 on April 4th, 2018, 7:18 pm, edited 1 time in total.
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Re: Thermodynamics B/C

Post by UTF-8 U+6211 U+662F » April 4th, 2018, 7:05 pm

Justin72835 wrote:
MattChina wrote:
Justin72835 wrote:Two gases occupy two containers, A and B. The gas in A, of volume 0.14 cubic meters, exerts a pressure of 1.18 MPa. The gas in B, of volume 0.21 cubic meters, exerts a pressure of 0.82 MPa. The containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant?
0.964?
Not quite. How did you get your answer?
Using the law of partial pressures 1.18 MPa * (0.14/0.35) + 0.82 MPa * (0.21/0.35) = 0.964 MPa

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Re: Thermodynamics B/C

Post by MattChina » April 4th, 2018, 7:08 pm

Justin72835 wrote:
MattChina wrote:
Justin72835 wrote:Two gases occupy two containers, A and B. The gas in A, of volume 0.14 cubic meters, exerts a pressure of 1.18 MPa. The gas in B, of volume 0.21 cubic meters, exerts a pressure of 0.82 MPa. The containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant?
0.964?
Not quite. How did you get your answer?

(P1V1/Vf)+(P2V2/Vf)
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Re: Thermodynamics B/C

Post by Justin72835 » April 4th, 2018, 7:22 pm

Nevermind, both of you (UTF-8 U+6211 U+662F and MattChina) are right. I messed up my calculations beforehand :cry:

Anyways, great job to both of you and sorry for the confusion! I think it's MattChina's turn now.
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Re: Thermodynamics B/C

Post by MattChina » April 4th, 2018, 7:38 pm

Lets do this. What is the best way to increase the efficiency of a carnot engine?
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Re: Thermodynamics B/C

Post by Justin72835 » April 5th, 2018, 4:20 pm

MattChina wrote:Lets do this. What is the best way to increase the efficiency of a carnot engine?
[math]e=1-\frac{Tc}{Th}[/math]
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Re: Thermodynamics B/C

Post by UTF-8 U+6211 U+662F » April 6th, 2018, 7:32 pm

Justin72835 wrote:
MattChina wrote:Lets do this. What is the best way to increase the efficiency of a carnot engine?
[math]e=1-\frac{Tc}{Th}[/math]
Increase the ratio of hot temperature to cold temperature

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Re: Thermodynamics B/C

Post by Justin72835 » April 6th, 2018, 7:40 pm

UTF-8 U+6211 U+662F wrote:
Justin72835 wrote:
MattChina wrote:Lets do this. What is the best way to increase the efficiency of a carnot engine?
[math]e=1-\frac{Tc}{Th}[/math]
Increase the ratio of hot temperature to cold temperature
Oh, I completely misread that question. :(
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Re: Thermodynamics B/C

Post by MattChina » April 7th, 2018, 7:59 am

UTF-8 U+6211 U+662F wrote:
Justin72835 wrote:
MattChina wrote:Lets do this. What is the best way to increase the efficiency of a carnot engine?
[math]e=1-\frac{Tc}{Th}[/math]
Increase the ratio of hot temperature to cold temperature
correct. your turn
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