## Hovercraft B/C

Moderator
Posts: 480
Joined: December 6th, 2013, 1:56 pm
State: TX
Location: Austin, Texas

### Re: Hovercraft B/C

Suppose I have a bowling ball with a diameter of 25 centimeters. What is the largest mass it can have such that it floats in corn syrup (specific gravity = 1.4)?
$\frac{m}{\frac43\pi r^3} = \frac{m}{\frac43\pi (12.5 cm)^3} = 1.4*1 \frac{g}{cm^3}$
$m = 1.4 \frac{g}{cm^3} * \frac43\pi (12.5 cm)^3 = 11453.7 g = 11.45 kg$
Looks good to me. Your turn!
University of Texas at Austin '22
Seven Lakes High School '18
Beckendorff Junior High '14

UTF-8 U+6211 U+662F
Exalted Member
Posts: 1518
Joined: January 18th, 2015, 7:42 am
Division: C
State: PA

### Re: Hovercraft B/C

All right! Given a graph of v vs t, how do you find the displacement traveled? What about the distance?

Moderator
Posts: 480
Joined: December 6th, 2013, 1:56 pm
State: TX
Location: Austin, Texas

### Re: Hovercraft B/C

All right! Given a graph of v vs t, how do you find the displacement traveled? What about the distance?
a. $\int^{b}_{a} v(t) dt$
b. $\int^{b}_{a} |v(t)| dt$
University of Texas at Austin '22
Seven Lakes High School '18
Beckendorff Junior High '14

UTF-8 U+6211 U+662F
Exalted Member
Posts: 1518
Joined: January 18th, 2015, 7:42 am
Division: C
State: PA

### Re: Hovercraft B/C

All right! Given a graph of v vs t, how do you find the displacement traveled? What about the distance?
a. $\int^{b}_{a} v(t) dt$
b. $\int^{b}_{a} |v(t)| dt$
Area under the curve for the unitiated in calculus (signed area for a and unsigned for b)

Moderator
Posts: 480
Joined: December 6th, 2013, 1:56 pm
State: TX
Location: Austin, Texas

### Re: Hovercraft B/C

All right! Given a graph of v vs t, how do you find the displacement traveled? What about the distance?
a. $\int^{b}_{a} v(t) dt$
b. $\int^{b}_{a} |v(t)| dt$
Area under the curve for the unitiated in calculus (signed area for a and unsigned for b)
Suppose you have a contracting star whose new radius is 1/x as big as the old radius.

a. How much faster does the star spin?
b. By what factor does its rotational kinetic energy change?
University of Texas at Austin '22
Seven Lakes High School '18
Beckendorff Junior High '14

MattChina
Member
Posts: 225
Joined: February 12th, 2017, 8:06 am
Division: B
State: NY
Location: somewhere over the rainbow

### Re: Hovercraft B/C

a. $\int^{b}_{a} v(t) dt$
b. $\int^{b}_{a} |v(t)| dt$
Area under the curve for the unitiated in calculus (signed area for a and unsigned for b)
Suppose you have a contracting star whose new radius is 1/x as big as the old radius.

a. How much faster does the star spin?
b. By what factor does its rotational kinetic energy change?
a. x^2 faster
b. x^2
2019 events: Water Quality, Battery Buggy, Elastic Launch Glider, Density Lab, Circuit Lab, Thermodynamics
R.C Murphy Co-Captain
Dank Memes Area Homeschool Team member

UTF-8 U+6211 U+662F
Exalted Member
Posts: 1518
Joined: January 18th, 2015, 7:42 am
Division: C
State: PA

### Re: Hovercraft B/C

It's been a while, so I guess I'll ask a question.

Consider a basketball player throwing a ball into the hoop. The ball is 625 g, and the basketball player throws it at 10 m/s at 65 degrees to the horizontal. Neglect air resistance.

1) Find the force that acts on the ball once it leaves the player's hand.

2) A regulation height hoop is 10 feet tall. Find the distance from the hoop he needs to be if he shoots the ball from just above his head and he is 1.8 m tall.

Edit: Wait hovercraft is being replaced next year

Nydauron
Member
Posts: 22
Joined: March 20th, 2018, 8:10 pm
State: IL
Location: Cornfields...

### Re: Hovercraft B/C

It's been a while, so I guess I'll ask a question.

Consider a basketball player throwing a ball into the hoop. The ball is 625 g, and the basketball player throws it at 10 m/s at 65 degrees to the horizontal. Neglect air resistance.

1) Find the force that acts on the ball once it leaves the player's hand.

2) A regulation height hoop is 10 feet tall. Find the distance from the hoop he needs to be if he shoots the ball from just above his head and he is 1.8 m tall.

Edit: Wait hovercraft is being replaced next year
1) The forces that are acting on the ball once the ball leaves the player’s hand is just the force of gravity.
$F_g = mg$
$F_g = 0.625 * 9.8$
$F_g = 6.125 N$

2)
$\Delta y = v_yt + \frac{gt^2}{2}$
$\frac{10}{3.28} - 1.8 = 10sin65\degree t- 4.9t^2$
$t = 0.15s, 1.7s$

$gt = v_f - v_i$
$-9.8 * 0.15 = v_f - 10sin65\degree$
$v_f = 7.593 m/s$

$-9.8 * 1.7 = v_f - 10sin65\degree$
$v_f = -7.593 m/s$

Since the velocity is negative at 1.7 seconds, $t = 1.7$ will be used to find the distance in the x direction.

$\Delta x = v_xt$
$\Delta x = 10cos65\degree * 1.7$
$\Delta x = 7.184 m$
Conant 19'
UIUC 23'
Member of The Builder Cult
2018 State - 2nd MTV | 3rd Hovercraft
2019 State - 5th MTV | 5th Sounds
Physics is the only real science
Change my mind

Userpage

UTF-8 U+6211 U+662F
Exalted Member
Posts: 1518
Joined: January 18th, 2015, 7:42 am
Division: C
State: PA

### Re: Hovercraft B/C

It's been a while, so I guess I'll ask a question.

Consider a basketball player throwing a ball into the hoop. The ball is 625 g, and the basketball player throws it at 10 m/s at 65 degrees to the horizontal. Neglect air resistance.

1) Find the force that acts on the ball once it leaves the player's hand.

2) A regulation height hoop is 10 feet tall. Find the distance from the hoop he needs to be if he shoots the ball from just above his head and he is 1.8 m tall.

Edit: Wait hovercraft is being replaced next year
1) The forces that are acting on the ball once the ball leaves the player’s hand is just the force of gravity.
$F_g = mg$
$F_g = 0.625 * 9.8$
$F_g = 6.125 N$

2)
$\Delta y = v_yt + \frac{gt^2}{2}$
$\frac{10}{3.28} - 1.8 = 10sin65\degree t- 4.9t^2$
$t = 0.15s, 1.7s$

$gt = v_f - v_i$
$-9.8 * 0.15 = v_f - 10sin65\degree$
$v_f = 7.593 m/s$

$-9.8 * 1.7 = v_f - 10sin65\degree$
$v_f = -7.593 m/s$

Since the velocity is negative at 1.7 seconds, $t = 1.7$ will be used to find the distance in the x direction.

$\Delta x = v_xt$
$\Delta x = 10cos65\degree * 1.7$
$\Delta x = 7.184 m$
Okay, hovercraft is gone next year, so I guess there won't be any more questions, but yep, that's right (interestingly, if you used 0.15 s, it would've given you the distance required if he wanted to shoot the basketball through the bottom of the hoop and out the top).