Machines B/C

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Creationist127
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Re: Machines B/C

Postby Creationist127 » September 17th, 2019, 9:04 am

A wedge is 1 inch thick and has a 25* angle at its narrow edge. It is placed with the thin edge in a crack in a block of wood. If 5 newtons of force is exerted on the end, how much force will the wedge split the block with?
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Re: Machines B/C

Postby amk578 » September 17th, 2019, 9:52 am

A wedge is 1 inch thick and has a 25* angle at its narrow edge. It is placed with the thin edge in a crack in a block of wood. If 5 newtons of force is exerted on the end, how much force will the wedge split the block with?
11.25 N or 10 N w/ sig figs
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Re: Machines B/C

Postby Creationist127 » September 17th, 2019, 10:26 am

A wedge is 1 inch thick and has a 25* angle at its narrow edge. It is placed with the thin edge in a crack in a block of wood. If 5 newtons of force is exerted on the end, how much force will the wedge split the block with?
11.25 N or 10 N w/ sig figs
Correct, and sorry about the sig figs. Your turn!
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Re: Machines B/C

Postby amk578 » September 18th, 2019, 5:04 am

Which of the following screws has the highest mechanical advantage?

a) a screw with a (1/2) inch radius with 10 threads per inch
b) a screw with a (1/2) inch radius with 12 threads per inch
c) a screw with a (1/4) inch radius and 10 threads per inch
d) a screw with a (1/4) inch radius and 12 threads per inch
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Re: Machines B/C

Postby CPScienceDude » September 18th, 2019, 7:21 am

B?
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Re: Machines B/C

Postby amk578 » September 18th, 2019, 1:56 pm

B?
Correct, your turn!
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Re: Machines B/C

Postby CPScienceDude » September 18th, 2019, 4:56 pm

A seesaw's short side is 0.8m long, and a long side that is 2.4m long. A mass of 50kg sits on the short, and a mass of 70kg is dropped onto the long side.

A) What is the ideal mechanical advantage of the seesaw?
B) If the larger mass exerts a force of 850 N on the seesaw as it falls onto the effort side, how much does the smaller mass accelerate upward (m/s^2)?
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Re: Machines B/C

Postby JoeyC » September 19th, 2019, 1:08 pm

A) 2.4/.8 = 3
B) Including the effects of gravity:
F=ma
a=F//m
F= Force of falling block * IMA - Force of gravity on stationary block
m = 50 kg
a=F/m
a = (850 N * 3 - 50 kg*9.81 m/s^2)/50kg = 41.19 m/s^2
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Re: Machines B/C

Postby CPScienceDude » September 19th, 2019, 6:40 pm

Looks good! Your turn
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Re: Machines B/C

Postby JoeyC » September 21st, 2019, 5:29 pm

Someone else ask the question lol.
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