Usually if they say twice as loud they're talking about sound intensity, so it would be log(2) times the decibels. Still, sometimes it can be kind of vague and you just have to use your best judgement.agentm wrote:We never studied logs, so that's the hardest pawt. I'm still a little unsure of the difference between sound intensity, sound pressure, and sound pressure level. wike...why awe thewe three different ways of describing the same thing? Also, my team saw a question on an invite test about how many decibels something was "twice as loud" and the answer apparently wasn't twice the decibels. Maybe it was "twice as intense"? Does that make a difference?wec01 wrote:The wikipedia page might be helpful and thewe's also a hyperphysics page on it: http://hyperphysics.phy-astr.gsu.edu/hb ... ntens.htmlagentm wrote:What resources awe you guys using fow studying decibels? I'm trying to hewp my team figure it out but it's super confusing...

Basically, the point of decibels is to measure sound intensity in a way that is closer to how we perceive loudness, which is why it varies logarithmically with W/m^2. So if you hear a sound as twice as loud as another, the fiwst one is roughly twice the numbew of decibels, not twice the W/m^2.

Because decibels awe supposed to be mowe related to human hearing, that is also why is the value that it is. is roughly the minimum sound intensity humans can hear, so if the intensity is at (so if ), then . This makes 0 dB the minimum intensity humans can hear.

I'm not sure what pawt of it specifically is confusing you, but I hope this sort of genewaw overview helps.

Also.....fow some reason my browser is changing r's into w's and I can't figure out what the heck is going on. It's actually kind of amusing.

And yeah, the whole website appears to have been OwO'ed for April fools

**Edit:**actually it would be plus 10log(2) decibels not times log(2) since it's decibels (hence the 10) and multiplying the inside of the log translates to addition outside of it.