Circuit Lab B/C

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Re: Circuit Lab B/C

Postby UTF-8 U+6211 U+662F » October 11th, 2018, 4:40 pm

What is the difference of total resistance of a circuit with 3 resistors of 6 ohms each arranged in a series vs parallel?
Series: 18 ohms, Parallel: 2 ohms

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Re: Circuit Lab B/C

Postby MattChina » October 11th, 2018, 4:44 pm

What is the difference of total resistance of a circuit with 3 resistors of 6 ohms each arranged in a series vs parallel?
Series: 18 ohms, Parallel: 2 ohms
yep
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Re: Circuit Lab B/C

Postby Jacobi » October 11th, 2018, 5:02 pm

What is the difference of total resistance of a circuit with 3 resistors of 6 ohms each arranged in a series vs parallel?
Well, it depends.
The resistance in series is 18 ohms (sum).  The resistance in parallel is 2 ohms ([math]\frac{1}{\Sigma\frac{1}{R}}[/math]). The difference is 16 ohms.
When resistors are placed in series, the electrons have to go through multiple blockages to complete the circuit.  Thus, the total resistance is greater.  When resistors are placed in parallel, the electrons have multiple pathways, and thus they encounter less overall resistance.
Take your pick.

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Re: Circuit Lab B/C

Postby MattChina » October 11th, 2018, 5:03 pm

What is the difference of total resistance of a circuit with 3 resistors of 6 ohms each arranged in a series vs parallel?
Well, it depends.
The resistance in series is 18 ohms (sum).  The resistance in parallel is 2 ohms ([math]\frac{1}{\Sigma\frac{1}{R}}[/math]). The difference is 16 ohms.
When resistors are placed in series, the electrons have to go through multiple blockages to complete the circuit.  Thus, the total resistance is greater.  When resistors are placed in parallel, the electrons have multiple pathways, and thus they encounter less overall resistance.
Take your pick.
Questions was already answered
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Re: Circuit Lab B/C

Postby Jacobi » October 11th, 2018, 5:05 pm

What is the difference of total resistance of a circuit with 3 resistors of 6 ohms each arranged in a series vs parallel?
Well, it depends.
The resistance in series is 18 ohms (sum).  The resistance in parallel is 2 ohms ([math]\frac{1}{\Sigma\frac{1}{R}}[/math]). The difference is 16 ohms.
When resistors are placed in series, the electrons have to go through multiple blockages to complete the circuit.  Thus, the total resistance is greater.  When resistors are placed in parallel, the electrons have multiple pathways, and thus they encounter less overall resistance.
Take your pick.
Questions was already answered
Sorry.

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Re: Circuit Lab B/C

Postby UTF-8 U+6211 U+662F » October 11th, 2018, 5:34 pm

Give a real-world function of a capacitor.

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Re: Circuit Lab B/C

Postby PM2017 » October 11th, 2018, 6:10 pm

What is the difference of total resistance of a circuit with 3 resistors of 6 ohms each arranged in a series vs parallel?
6*3 ohms - (3(1/6))^(-1) ohms = 18 ohms - 2 ohms  16 ohms
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Re: Circuit Lab B/C

Postby MattChina » October 11th, 2018, 7:18 pm

What is the difference of total resistance of a circuit with 3 resistors of 6 ohms each arranged in a series vs parallel?
6*3 ohms - (3(1/6))^(-1) ohms = 18 ohms - 2 ohms  16 ohms
Question was already answered and there is a new question up but yes that is correct
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Re: Circuit Lab B/C

Postby mdv2o5 » October 12th, 2018, 6:10 am

Give a real-world function of a capacitor.
FULL BRIDGE RECTIFIER ... or pretty much any rectifier that turns AC into DC (e.g. switching power supplies).
If the above answer is acceptable, what does it mean for breakdown to occur in a pn junction?

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Re: Circuit Lab B/C

Postby UTF-8 U+6211 U+662F » October 12th, 2018, 2:20 pm

Give a real-world function of a capacitor.
FULL BRIDGE RECTIFIER ... or pretty much any rectifier that turns AC into DC (e.g. switching power supplies).
If the above answer is acceptable, what does it mean for breakdown to occur in a pn junction?
Yep.
Breakdown is a rapid increase in reverse current past the maximum voltage in reverse biased conditions


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