Welcome to the 2018-2019 season! I'll start with some basics:

A speaker produces a sound with an intensity of 1 x 10^-4 W/m^2. What is the intensity, in decibels, of the sound produced by 4 of these speakers?

Re: Sounds Of Music C

Posted: September 5th, 2018, 6:01 pm

by mjcox2000

10^-4 W/m^2 is 80dB. A factor of 4 is an additional 6dB, so the configuration has a total sound intensity of 86dB (assuming only constructive interference).

Re: Sounds Of Music C

Posted: September 5th, 2018, 6:03 pm

by goblinrum

Hi there, here is my answer:
forgive my formatting

dB = 10 log I / I (threshold intensity ) = 10 log 4(1 x 10^-4 W/m^2) / 1 x 10^-12 W/m^2 = 86dB, so final is 86dB

Here is my question : A soprano saxophone is considered an open pipe resonator. If the pipe was straightened
out it would be 65 cm long. Using 343 m/s for the speed of sound, find the lowest
frequency that can be played, ignoring end corrections.

A wee bit word problem

Re: Sounds Of Music C

Posted: September 5th, 2018, 6:22 pm

by Darkmatter7

goblinrum wrote:Hi there, here is my answer:
forgive my formatting

dB = 10 log I / I (threshold intensity ) = 10 log 4(1 x 10^-4 W/m^2) / 1 x 10^-12 W/m^2 = 86dB, so final is 86dB

Here is my question : A soprano saxophone is considered an open pipe resonator. If the pipe was straightened
out it would be 65 cm long. Using 343 m/s for the speed of sound, find the lowest
frequency that can be played, ignoring end corrections.

A wee bit word problem

So the fundamental frequency is equal to 2/1 Length. 65 cm * 2 = 130. 343 m/s = 1.3 m * frequency. After calculating, I got ~364 Hz.

Re: Sounds Of Music C

Posted: September 5th, 2018, 6:23 pm

by Darkmatter7

Darkmatter7 wrote:

goblinrum wrote:Hi there, here is my answer:
forgive my formatting

dB = 10 log I / I (threshold intensity ) = 10 log 4(1 x 10^-4 W/m^2) / 1 x 10^-12 W/m^2 = 86dB, so final is 86dB

Here is my question : A soprano saxophone is considered an open pipe resonator. If the pipe was straightened
out it would be 65 cm long. Using 343 m/s for the speed of sound, find the lowest
frequency that can be played, ignoring end corrections.

A wee bit word problem

So the fundamental frequency is equal to 2/1 Length. 65 cm * 2 = 130. 343 m/s = 1.3 m * frequency. After calculating, I got ~364 Hz.

Sorry, forgot to tell you that you got the correct answer on my question

Re: Sounds Of Music C

Posted: September 5th, 2018, 6:37 pm

by goblinrum

Darkmatter7 wrote:

Darkmatter7 wrote:

goblinrum wrote:Hi there, here is my answer:
forgive my formatting

dB = 10 log I / I (threshold intensity ) = 10 log 4(1 x 10^-4 W/m^2) / 1 x 10^-12 W/m^2 = 86dB, so final is 86dB

Here is my question : A soprano saxophone is considered an open pipe resonator. If the pipe was straightened
out it would be 65 cm long. Using 343 m/s for the speed of sound, find the lowest
frequency that can be played, ignoring end corrections.

A wee bit word problem

So the fundamental frequency is equal to 2/1 Length. 65 cm * 2 = 130. 343 m/s = 1.3 m * frequency. After calculating, I got ~364 Hz.

Sorry, forgot to tell you that you got the correct answer on my question

Did you just do
(343 m/s) / 1.3 m is 364Hz????

Re: Sounds Of Music C

Posted: September 5th, 2018, 6:39 pm

by HeadphoneMonster

Darkmatter7 wrote:

goblinrum wrote:Hi there, here is my answer:
forgive my formatting

dB = 10 log I / I (threshold intensity ) = 10 log 4(1 x 10^-4 W/m^2) / 1 x 10^-12 W/m^2 = 86dB, so final is 86dB

Here is my question : A soprano saxophone is considered an open pipe resonator. If the pipe was straightened
out it would be 65 cm long. Using 343 m/s for the speed of sound, find the lowest
frequency that can be played, ignoring end corrections.

A wee bit word problem

So the fundamental frequency is equal to 2/1 Length. 65 cm * 2 = 130. 343 m/s = 1.3 m * frequency. After calculating, I got ~364 Hz.

I think you might be wrong or I might be wrong
Freq= speed/wavelength F= 343 /(2*.65meters)= 263.846 or 264 Hz.

Re: Sounds Of Music C

Posted: September 5th, 2018, 6:39 pm

by Darkmatter7

goblinrum wrote:

Darkmatter7 wrote:

Darkmatter7 wrote:
So the fundamental frequency is equal to 2/1 Length. 65 cm * 2 = 130. 343 m/s = 1.3 m * frequency. After calculating, I got ~364 Hz.

Sorry, forgot to tell you that you got the correct answer on my question

Did you just do
(343 m/s) / 1.3 m is 364Hz????

264Hz. I miss typed -.-

Re: Sounds Of Music C

Posted: September 6th, 2018, 8:20 am

by Darkmatter7

A Solid has a bulk modulus of 2.3 × 10^7 N/m^2 and a density of 8.05 g/cm^3. What is the speed of sound in this solid?

Re: Sounds Of Music C

Posted: September 6th, 2018, 8:48 am

by epicdragon44

Using the equation for speed of sound in a medium, V = sqrt(B/R), where B is the Bulk Modulus and R is rho, the density of the material.
Let's plug in the variables: sqrt((2.3*10^7)/(8.05*(10^3))) (converting density to metric units), which gives us 2857 m/s (if I didn't somehow mess up the calculation.