### Shock Value B

Posted:

**June 11th, 2009, 7:25 pm**Discussion for Shock Value B.

Science Olympiad Student Center

https://scioly.org/forums/

Page **1** of **14**

Posted: **June 11th, 2009, 7:25 pm**

Discussion for Shock Value B.

Posted: **August 17th, 2009, 1:54 pm**

Circuit Lab Wiki

Trial Event Rules: http://soinc.org/sites/default/files/up ... kvalue.pdf

Thoughts?

Trial Event Rules: http://soinc.org/sites/default/files/up ... kvalue.pdf

Thoughts?

Posted: **August 25th, 2009, 11:56 am**

Why does increased resistance mean increased voltage?

Posted: **August 25th, 2009, 12:30 pm**

Ohm's Law states: E = I x R

Where:

R = Resistance in Ohms

E = Electromotive Force in Volts

I = Current in Amperes

If R increases, E must also increase in order for I to remain the same.

In a simple circuit with only 1 EMF source, 1 resistance and 1 current path, increasing the resistance will cause current ( I ) to decrease. In circuits with more than a single resistance in series, each resistance uses (drops) only a portion of the total (applied) voltage. Increasing one of the resistances causes the voltage it drops to increase. Since the applied voltage remains the same, voltage dropped by the other series resistors must decrease.

For Series Circuits:

E(total) = E(R1) + E(R2).... + E(Rn)

R(total) = R1 + R2.... + Rn

I(total) = I(R1) = I(R2).... = I(Rn)

For Parallel Circuits:

E(total) = E(R1) = E(R2).... = E(Rn)

R(total) = 1/[(1/R1) + (1/R2).... + (1/Rn)]

I(total) = I(R1) + I(R2).... + I(Rn)

Edit: Corrected typo in equation for Ohm's Law

Where:

R = Resistance in Ohms

E = Electromotive Force in Volts

I = Current in Amperes

If R increases, E must also increase in order for I to remain the same.

In a simple circuit with only 1 EMF source, 1 resistance and 1 current path, increasing the resistance will cause current ( I ) to decrease. In circuits with more than a single resistance in series, each resistance uses (drops) only a portion of the total (applied) voltage. Increasing one of the resistances causes the voltage it drops to increase. Since the applied voltage remains the same, voltage dropped by the other series resistors must decrease.

For Series Circuits:

E(total) = E(R1) + E(R2).... + E(Rn)

R(total) = R1 + R2.... + Rn

I(total) = I(R1) = I(R2).... = I(Rn)

For Parallel Circuits:

E(total) = E(R1) = E(R2).... = E(Rn)

R(total) = 1/[(1/R1) + (1/R2).... + (1/Rn)]

I(total) = I(R1) + I(R2).... + I(Rn)

Edit: Corrected typo in equation for Ohm's Law

Posted: **August 25th, 2009, 6:20 pm**

You seem to have misstated Ohm's Law. In actuality, Ohm's Law states, using your notation, that E = I x R. Good explanation, otherwise.

To add to that, it is not the case that increasing the resistance in a circuit will increase the voltage. The correct interpretation of this information is that: if you increase the resistance in a circuit, and you want to maintain the same current, you must do something to increase the voltage applied to the circuit (typically by adding a battery or something). A good way to approach this is to treat current as a dependent variable: I = E/R. You cannot do anything to directly change the current flowing through the circuit; rather, you must increase the voltage or decrease the resistance to increase the flow of current (or vice versa for the opposite effect).

To add to that, it is not the case that increasing the resistance in a circuit will increase the voltage. The correct interpretation of this information is that: if you increase the resistance in a circuit, and you want to maintain the same current, you must do something to increase the voltage applied to the circuit (typically by adding a battery or something). A good way to approach this is to treat current as a dependent variable: I = E/R. You cannot do anything to directly change the current flowing through the circuit; rather, you must increase the voltage or decrease the resistance to increase the flow of current (or vice versa for the opposite effect).

Posted: **August 25th, 2009, 7:17 pm**

Correct. If the voltage were constant, increasing the resistance would decrease the current. Increasing the resistance would not increase the voltage on its own under most circumstances, rather it would decrease the current. If one were to adjust the voltage properly, they could maintain the same current load.

Posted: **August 25th, 2009, 11:41 pm**

You are correct, Ohms Law should be: E = I x R

I have corrected my previous post.

This change in voltage is easily demonstrated with a few resistors, a battery and a voltmeter.

I have corrected my previous post.

While this is true, I didn't want to increase the applied voltage to maintain the same current. I wanted to show the effect that changing one resistance in a series circuit would have on the circuit.The correct interpretation of this information is that: if you increase the resistance in a circuit, and you want to maintain the same current, you must do something to increase the voltage applied to the circuit

If only one resistance in a series circuit containing more than one resistance is increased, the voltage drop across THAT resistance WILL increase. Since the applied voltage remains the same, and the sum of the voltages dropped by each resistor is equal to the applied voltage, the voltage dropped by the other resistors in the circuit must decrease. The current will also decrease due to the increase in total resistance.it is not the case that increasing the resistance in a circuit will increase the voltage.

This change in voltage is easily demonstrated with a few resistors, a battery and a voltmeter.

Posted: **August 26th, 2009, 9:28 am**

I see. Increasing resistance doesn't increase voltage, it decreases current (under most circumstances). Thanks!

Posted: **August 26th, 2009, 9:46 am**

Correct. When dealing with individual resistors, we can apply Ohms Law to each one, using the information posted above about voltage and current in series and parallel circuits.You are correct, Ohms Law should be: E = I x R

I have corrected my previous post.

If only one resistance in a series circuit containing more than one resistance is increased, the voltage drop across THAT resistance WILL increase. Since the applied voltage remains the same, and the sum of the voltages dropped by each resistor is equal to the applied voltage, the voltage dropped by the other resistors in the circuit must decrease. The current will also decrease due to the increase in total resistance.

This change in voltage is easily demonstrated with a few resistors, a battery and a voltmeter.

Total voltage, no, but voltage through that individual resistor in a series circuit (see fleet's post above). In a parallel circuit, voltage is constant across all branches, so increasing resistance of one or all branches will not affect the voltage through them, just the current. Of course, you're usually going to be dealing with a combination of series and parallel.I see. Increasing resistance doesn't increase voltage, it decreases current (under most circumstances). Thanks!

Posted: **August 27th, 2009, 7:04 pm**

Oh, I see what you were getting at. That makes sense. Sorry if I seemed overzealous there.While this is true, I didn't want to increase the applied voltage to maintain the same current. I wanted to show the effect that changing one resistance in a series circuit would have on the circuit.The correct interpretation of this information is that: if you increase the resistance in a circuit, and you want to maintain the same current, you must do something to increase the voltage applied to the circuit