Thermodynamics B/C
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- WhatScience?
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Re: Thermodynamics B/C
A person wants to replace the window on their house, but they don't want their heating and cooling bills to change. The original window on the wall of the house has area A, thickness d, and is made out of glass that has a thermal conduction constant k. Which one of the following changes could be made to the window that would leave the rate of thermal conduction the same as the original window?
A: double the area, cut the thickness in half, cut the k constant in half
B: cut the area in half, cut the thickness in half, and double the k constant
C: quadruple the area, double the thickness, cut the k constant in half
D: double the area, double the thickness, quadruple the k constant
A: double the area, cut the thickness in half, cut the k constant in half
B: cut the area in half, cut the thickness in half, and double the k constant
C: quadruple the area, double the thickness, cut the k constant in half
D: double the area, double the thickness, quadruple the k constant
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Re: Thermodynamics B/C
When site rollover occurs from the 2017 to 2018 seasons, the old event threads get archived so that new threads can be created. This is done so that discussions about new rules and updates can happen in their own threads, as opposed to continuations of threads from the previous year.WhatScience? wrote:I do not know what happened to this but 2018!!! Thermo!!!!
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- WhatScience?
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Re: Thermodynamics B/C
Oh, thx.EastStroudsburg13 wrote:When site rollover occurs from the 2017 to 2018 seasons, the old event threads get archived so that new threads can be created. This is done so that discussions about new rules and updates can happen in their own threads, as opposed to continuations of threads from the previous year.WhatScience? wrote:I do not know what happened to this but 2018!!! Thermo!!!!
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Re: Thermodynamics B/C
ummm GuysWhatScience? wrote:A person wants to replace the window on their house, but they don't want their heating and cooling bills to change. The original window on the wall of the house has area A, thickness d, and is made out of glass that has a thermal conduction constant k. Which one of the following changes could be made to the window that would leave the rate of thermal conduction the same as the original window?
A: double the area, cut the thickness in half, cut the k constant in half
B: cut the area in half, cut the thickness in half, and double the k constant
C: quadruple the area, double the thickness, cut the k constant in half
D: double the area, double the thickness, quadruple the k constant
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Re: Thermodynamics B/C
D
Credits to Khan Academy lol.
Who was the scientist who came up with the basic ideas of the Second Law of Thermodynamics?
Credits to Khan Academy lol.
Who was the scientist who came up with the basic ideas of the Second Law of Thermodynamics?
Circuit Lab NY State Champion with legendary circuitologist Eric Wang
LONGEST DEFENDING ROCKS AND MINERALS REGIONAL CHAMPION OF EASTERN LONG ISLAND IN HISTORY ~4 YEARS AND COUNTING
LONGEST DEFENDING ROCKS AND MINERALS REGIONAL CHAMPION OF EASTERN LONG ISLAND IN HISTORY ~4 YEARS AND COUNTING
- WhatScience?
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Re: Thermodynamics B/C
Rudolf Julius Emanuel Clausis
A steel part that has the temperature of 700 degrees C is put into an oil bath to cool down. The bath must operate in between 25 and 30 degrees C. You want to use the smallest amount of oil possible to cool down the part. If the oil bath is starts at 25 C, what is the minimum amount of oil required of quench a steel part that is 175 grams?
specific heat of oil = 0.5 calories/gram C
specific heat of steel = 0.107 calories/gram C
A steel part that has the temperature of 700 degrees C is put into an oil bath to cool down. The bath must operate in between 25 and 30 degrees C. You want to use the smallest amount of oil possible to cool down the part. If the oil bath is starts at 25 C, what is the minimum amount of oil required of quench a steel part that is 175 grams?
specific heat of oil = 0.5 calories/gram C
specific heat of steel = 0.107 calories/gram C
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Re: Thermodynamics B/C
WhatScience? wrote:Rudolf Julius Emanuel Clausis
A steel part that has the temperature of 700 degrees C is put into an oil bath to cool down. The bath must operate in between 25 and 30 degrees C. You want to use the smallest amount of oil possible to cool down the part. If the oil bath is starts at 25 C, what is the minimum amount of oil required of quench a steel part that is 175 grams?
specific heat of oil = 0.5 calories/gram C
specific heat of steel = 0.107 calories/gram C
5018.3g
I have the ACT tomorrow why am I doing this lol
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Re: Thermodynamics B/C
If thermodynamic system a is in equilibrium with thermodynamic system c, and thermodynamic system c is in equilibrium with thermodynamic system b, thermodynamic systems a and b are also in equilibrium.
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Re: Thermodynamics B/C
Explain the difference in between entropy driven and enthalpy driven reactions.
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