Thermodynamics B/C

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Raleway
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Re: Thermodynamics B/C

Post by Raleway »

WhatScience? wrote:Explain the difference in between entropy driven and enthalpy driven reactions.
When using Gibb's Free Energy Equation (dG = dH - TdS) or any derivative form of that with Enthalpy and Entropy in it, that the larger of the two expressions (entropy or enthalpy) that make the reaction spontaneous will be said to have "driven" the reaction.

Question: When reading a phase change diagram. describe the kinetic energy at the triple point relative to the other three states' kinetic energy.
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Re: Thermodynamics B/C

Post by WhatScience? »

Raleway wrote: Question: When reading a phase change diagram. describe the kinetic energy at the triple point relative to the other three states' kinetic energy.
This is what I have in relation to a phase change diagram of water. Statements would be different for something like the diagram of carbon dioxide...

The triple point is at the highest average kinetic energy possible for a solid.

A gas' average kinetic energy will be higher than the triple point when the amount of pressure is above the triple point, but lower than the triple point when the pressure is lower than the triple point.

Since at most pressure levels, liquid has a freezing point and a boiling point, the average kinetic energy of a liquid can at any given pressure be both higher or lower than the average kinetic energy at the triple point.
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Re: Thermodynamics B/C

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Question: van der waals equation is a correction of the ideal gas law. In which three scenarios is it most applicable and what is the reasoning behind the changes made to the equation?
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Re: Thermodynamics B/C

Post by Kavar »

wzhang5460 wrote:D
Credits to Khan Academy lol.
I believe you are mistaken. The answer should be C if you cancel out the values correctly. Credits to Khan Academy ;) :D .
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Re: Thermodynamics B/C

Post by WhatScience? »

WhatScience? wrote:Question: van der waals equation is a correction of the ideal gas law. In which three scenarios is it most applicable and what is the reasoning behind the changes made to the equation?
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Re: Thermodynamics B/C

Post by WhatScience? »

answer the above question please
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Re: Thermodynamics B/C

Post by wzhang5460 »

Kavar wrote:
wzhang5460 wrote:D
Credits to Khan Academy lol.
I believe you are mistaken. The answer should be C if you cancel out the values correctly. Credits to Khan Academy ;) :D .
Sorry, I typed the wrong letter. Haha
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Re: Thermodynamics B/C

Post by WhatScience? »

WhatScience? wrote:
WhatScience? wrote:Question: van der waals equation is a correction of the ideal gas law. In which three scenarios is it most applicable and what is the reasoning behind the changes made to the equation?
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Re: Thermodynamics B/C

Post by raxu »

I only know two scenarios: when the molecules are relatively large (e.g. octane) and when there is strong intermolecular interactions (e.g. water vapor).

The equation is . The correction factor accounts for intermolecular interactions, and the correction factor accounts for size of gases.

The bob temperature scale is a linear temperature scale where at 1 atm, water freezes at 42°B and boils at 239°B. Convert -53 °C to °B.
Last edited by raxu on October 9th, 2017, 6:09 pm, edited 1 time in total.
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Re: Thermodynamics B/C

Post by WhatScience? »

raxu wrote:I only know two scenarios: when the molecules are relatively large (e.g. octane) and when there is strong intermolecular interactions (e.g. water vapor).

The equation is . The correction factor accounts for intermolecular interactions, and the correction factor accounts for size of gases.

The bob temperature scale is a linear temperature scale where at 1 atm, water freezes at 42°B and boils at 239°B. Convert -53 °C to °B.
The equation part is right but the three scenarios I was looking for was any scenario where the molecules are crowded together: High pressure, Low Temperature, and High Density

Either way, your turn.
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