Materials Science C
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Materials Science C
I was surprised to see that there wasn't a forum for this, so I'll start us off.
A. Give the common name of this compound.
B. Give the strict IUPAC system name of this compound. (Even though the common name is also generally accepted by the IUPAC.)
A. Give the common name of this compound.
B. Give the strict IUPAC system name of this compound. (Even though the common name is also generally accepted by the IUPAC.)
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Re: Materials Science C
Correct on both parts!wethose wrote:A) tert-butylcyclohexane
b) (1,1-dimethylethyl) cyclohexane Speaking in terms of hybridization, why do alkanes lack isomers?
Alkanes have structural isomers, of course. However, they do not have geometric isomers. This is because they contain only sigma bonds, which are able to freely rotate between all possible geometric configurations. In terms of hybridization, their carbons form bonds with 4 sp3 hybrid orbitals. Geometric isomers occur when pi bonds (in double and triple bonds) restrict rotation around the sigma bond. To form such geometric isomers, carbon atoms must contain sp or sp2 hybrid orbitals for sigma bonds and p orbitals for pi bonds.
I assume this covers the question, but I will wait for you to verify before I post another question.
University of Michigan Science Olympiad Div. C Event Lead
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Re: Materials Science C
Yep! Thanks for catching the structural vs geometric thing.. I'm new to this event lolTesel wrote:Correct on both parts!wethose wrote:A) tert-butylcyclohexane
b) (1,1-dimethylethyl) cyclohexane Speaking in terms of hybridization, why do alkanes lack isomers?
Alkanes have structural isomers, of course. However, they do not have geometric isomers. This is because they contain only sigma bonds, which are able to freely rotate between all possible geometric configurations. In terms of hybridization, their carbons form bonds with 4 sp3 hybrid orbitals. Geometric isomers occur when pi bonds (in double and triple bonds) restrict rotation around the sigma bond. To form such geometric isomers, carbon atoms must contain sp or sp2 hybrid orbitals for sigma bonds and p orbitals for pi bonds.
I assume this covers the question, but I will wait for you to verify before I post another question.
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Re: Materials Science C
Not a problem, it was still a good question!wethose wrote:Yep! Thanks for catching the structural vs geometric thing.. I'm new to this event lol
Below is a stress-strain curve characteristic of thermoplastic polymers:
Given that this graph uses engineering stress and strain values, why does the polymer show a rapid decrease in stress after the yield strength, then a plateau, then a gradual increase in stress before fracture?
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Re: Materials Science C
The polymer chains become increasingly oriented with the tensile axis, increasing the strength of the polymer (strain hardening)Tesel wrote:Not a problem, it was still a good question!wethose wrote:Yep! Thanks for catching the structural vs geometric thing.. I'm new to this event lol
Below is a stress-strain curve characteristic of thermoplastic polymers:
Given that this graph uses engineering stress and strain values, why does the polymer show a rapid decrease in stress after the yield strength, then a plateau, then a gradual increase in stress before fracture?
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Re: Materials Science C
Correct!IcsTam wrote:The polymer chains become increasingly oriented with the tensile axis, increasing the strength of the polymer (strain hardening)
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Re: Materials Science C
What is the Ziegler-Natta catalyst and what is its function?
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Re: Materials Science C
Ziegler natta catalyst is used in addition polymerization in order to control tacicity and eliminate branching, allowing to produce certain types of polymers that couldn't have produced otherwiseIcsTam wrote:What is the Ziegler-Natta catalyst and what is its function?
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1st place MIT Codebusters 2019-2020 1st place NYS Fermi Questions (2019), Astronomy and Codebusters (2021) Science Olympiad Founder's Scholarship winner
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Re: Materials Science C
Correct! Your turn.Name wrote:Ziegler natta catalyst is used in addition polymerization in order to control tacicity and eliminate branching, allowing to produce certain types of polymers that couldn't have produced otherwiseIcsTam wrote:What is the Ziegler-Natta catalyst and what is its function?
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