## Fermi Questions C

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### Re: Fermi Questions C

Tom_MS wrote:According to the shell theorem (essentially Gauss's law), the only mass that matters should be within a spherical shell at the radius being considered.

Vector calculus being useful XD
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### Re: Fermi Questions C

Tom_MS wrote:
Name wrote:Wait a screwed up the question. It is E0 but I should've said something like 3000 where the new mass is around E22 and radius is 1000 where the gravitational force is E1 stronger while on the surface

I feel like this is being overthought. According to the shell theorem (essentially Gauss's law), the only mass that matters should be within a spherical shell at the radius being considered. If you do the math, this gives a linearly decreasing force for a linearly decreasing radius. Thus, just taking the ratio of 5/6 (5000 km compared to around 6000 km) gives you fermi 0.

Wait hmm I checked the math and this seems correct. I probably screwed up something while doing the math earlier. The mass is porportional to volume which is radius cubed and is divided by radius squared so the force is linearly decreasing.
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### Re: Fermi Questions C

PM2017 wrote:What is the 273rd Fibonacci number?
To clarify, 0 will be considered the first Fibonacci number.

Attempt

A proton and electron are initially separated by 1 meter. After being released, they end up colliding due to their coulombic attraction. If the final kinetic energy (right before collision) of the two particles is converted almost entirely into rest mass energy of the particles released, how much mass is formed (kg)?

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### Re: Fermi Questions C

Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)
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### Re: Fermi Questions C

PM2017 wrote:Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)

Uh it's pretty easy to just google
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### Re: Fermi Questions C

Name wrote:
PM2017 wrote:Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)

Uh it's pretty easy to just google

It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.
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### Re: Fermi Questions C

whythelongface wrote:
Name wrote:
PM2017 wrote:Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)

Uh it's pretty easy to just google

It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.

Wait I was thinking of something else... The limit of the ratio between one Fibonacci number and the next is the golden ratio, as you get larger and larger numbers. So you just do (Phi)^(273-1).
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### Re: Fermi Questions C

PM2017 wrote:
whythelongface wrote:
Name wrote:
Uh it's pretty easy to just google

It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.

Wait I was thinking of something else... The limit of the ratio between one Fibonacci number and the next is the golden ratio, as you get larger and larger numbers. So you just do (Phi)^(273-1).

This is how I would do it.
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### Re: Fermi Questions C

Unome wrote:
PM2017 wrote:
whythelongface wrote:It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.

Wait I was thinking of something else... The limit of the ratio between one Fibonacci number and the next is the golden ratio, as you get larger and larger numbers. So you just do (Phi)^(273-1).

This is how I would do it.

Oops I appear to have read "fibonacci" as "factorial"

Yes, this seems to be the ideal way of doing it.
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### Re: Fermi Questions C

Time to restart this thread for now... b/c it'll be relevant next year!

With the hot air coming out of Donald Trump's mouth when he says cofveve, how many times would he need to repeat it in order to boil water? Whoever actually solves this (not you whythelongface) correctly gets a cookie!
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### Re: Fermi Questions C

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### Re: Fermi Questions C

Raleway wrote:Time to restart this thread for now... b/c it'll be relevant next year!

With the hot air coming out of Donald Trump's mouth when he says cofveve, how many times would he need to repeat it in order to boil water? Whoever actually solves this (not you whythelongface) correctly gets a cookie!

You should prob specify the amount of water lol and also current temp
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### Re: Fermi Questions C

NeilMehta wrote:
Raleway wrote:Time to restart this thread for now... b/c it'll be relevant next year!

With the hot air coming out of Donald Trump's mouth when he says cofveve, how many times would he need to repeat it in order to boil water? Whoever actually solves this (not you whythelongface) correctly gets a cookie!

You should prob specify the amount of water lol and also current temp

This is easy....
5x10^2 (He talks too much)
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### Re: Fermi Questions C

TheChiScientist wrote:
NeilMehta wrote:
Raleway wrote:Time to restart this thread for now... b/c it'll be relevant next year!

With the hot air coming out of Donald Trump's mouth when he says cofveve, how many times would he need to repeat it in order to boil water? Whoever actually solves this (not you whythelongface) correctly gets a cookie!

You should prob specify the amount of water lol and also current temp

This is easy....
5x10^2 (He talks too much)

What process did you use?
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### Re: Fermi Questions C

More or less the average word per tweet plus the theoretical "hot" air coming out at which rate it would take to make about 1 ml or water to reach 100C.
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