Tom_MS wrote:According to the shell theorem (essentially Gauss's law), the only mass that matters should be within a spherical shell at the radius being considered.
Vector calculus being useful XD
Tom_MS wrote:According to the shell theorem (essentially Gauss's law), the only mass that matters should be within a spherical shell at the radius being considered.
Tom_MS wrote:Name wrote:Wait a screwed up the question. It is E0 but I should've said something like 3000 where the new mass is around E22 and radius is 1000 where the gravitational force is E1 stronger while on the surface
I feel like this is being overthought. According to the shell theorem (essentially Gauss's law), the only mass that matters should be within a spherical shell at the radius being considered. If you do the math, this gives a linearly decreasing force for a linearly decreasing radius. Thus, just taking the ratio of 5/6 (5000 km compared to around 6000 km) gives you fermi 0.
PM2017 wrote:What is the 273rd Fibonacci number?
To clarify, 0 will be considered the first Fibonacci number.
PM2017 wrote:Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)
Name wrote:PM2017 wrote:Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)
Uh it's pretty easy to just google
whythelongface wrote:Name wrote:PM2017 wrote:Hmmm... I sort of made that question so the others would be able to learn the method of approximating fibbonacci numbers... (I'm pretty sure I know what you're doing, but I won't disclose it if you don't want it disclosed.)
Uh it's pretty easy to just google
It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.
PM2017 wrote:whythelongface wrote:Name wrote:
Uh it's pretty easy to just google
It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.
Wait I was thinking of something else... The limit of the ratio between one Fibonacci number and the next is the golden ratio, as you get larger and larger numbers. So you just do (Phi)^(273-1).
Unome wrote:PM2017 wrote:whythelongface wrote:It's just Stirling's Approximation of Factorials. It's not exactly a trade secret.
Wait I was thinking of something else... The limit of the ratio between one Fibonacci number and the next is the golden ratio, as you get larger and larger numbers. So you just do (Phi)^(273-1).
This is how I would do it.
Raleway wrote:Time to restart this thread for now... b/c it'll be relevant next year!
With the hot air coming out of Donald Trump's mouth when he says cofveve, how many times would he need to repeat it in order to boil water? Whoever actually solves this (not you whythelongface) correctly gets a cookie!
NeilMehta wrote:Raleway wrote:Time to restart this thread for now... b/c it'll be relevant next year!
With the hot air coming out of Donald Trump's mouth when he says cofveve, how many times would he need to repeat it in order to boil water? Whoever actually solves this (not you whythelongface) correctly gets a cookie!
You should prob specify the amount of water lol and also current temp
TheChiScientist wrote:NeilMehta wrote:Raleway wrote:Time to restart this thread for now... b/c it'll be relevant next year!
With the hot air coming out of Donald Trump's mouth when he says cofveve, how many times would he need to repeat it in order to boil water? Whoever actually solves this (not you whythelongface) correctly gets a cookie!
You should prob specify the amount of water lol and also current temp
This is easy....
5x10^2 (He talks too much)
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